Please help me convert equation to matlab code.

조회 수: 100(최근 30일)
adi putra
adi putra 2018년 4월 1일
댓글: Walter Roberson 2022년 8월 18일
Deal all.
I need you help to convert this equation to matlab code
I spend a lot of time to write it but it doesn't work. Thank you.
  댓글 수: 1
Walter Roberson
Walter Roberson 2018년 4월 1일
Are you permitted to use the symbolic toolbox?
Is the question about providing some kind of symbolic proof, or is it about calculation of the formula using finite precision and a particular numeric input?

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답변(8개)

Birdman
Birdman 2018년 4월 1일
편집: Birdman 2018년 4월 1일
Basically, Symbolic Toolbox will help you:
syms y(x) n
f(x)=symsum((-1).^n*(x.^(2*n+1))/factorial(2*n+1),n,0,Inf)
  댓글 수: 4
Birdman
Birdman 2018년 4월 1일
Yes, I just now edited it Roger.

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Roger Stafford
Roger Stafford 2018년 4월 1일
N = 100; % <-- Choose some large number
s = x;
for n = 2*N-1:-2:1
s = x - s*x^2/((n+2)*(n+1));
end
(I think you meant to take the limit as N approaches infinity, not x.)

kalai selvi
kalai selvi 2020년 9월 15일
pls answer this question ...how to write the equation into code
  댓글 수: 2
Walter Roberson
Walter Roberson 2020년 9월 15일
π is written as pi in MATLAB.
exp of an expression is written as exp(expression) in MATLAB.
is written as sqrt(expression) in MATLAB.

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kalai selvi
kalai selvi 2020년 9월 16일
How to write a code on IOTA filter in fbmc system
  댓글 수: 2
kalai selvi
kalai selvi 2020년 9월 23일
thank you

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Kunwar Pal Singh
Kunwar Pal Singh 2021년 4월 26일
please answer this....how to write this equation into MATLAB CODE
  댓글 수: 1
Walter Roberson
Walter Roberson 2021년 4월 26일
%these variables must be defined in a way appropriate for your situation
S_N = rand() * 10
theta = randn() * 2 * pi
l = randi([2 10])
b_1 = rand()
c_11 = rand()
t_year = randi([1950 2049])
d_11 = rand()
t_1 = rand()
t_x = t_1 + rand()
lambda_a = randi([500 579])
LOTF_a = rand()
P = rand()
K_l = rand()
k_0 = rand()
t_tau = randi(10)
overhaulcost_a = 1000 + rand()*100
%the work
syms t
part1 = int(S_N .* cos(theta) .* l .* b_1 .* t_year .* d_11, t, t_1, t_x);
part2 = int(lambda_a .* LOTF_a, t, t_1, t_x);
part3 = int(P*K_l .* t_year + P .* k_0 .* l .* l .* t_tau, t, t_1, t_x);
part4 = overhaulcost_a ;
result = part1 - part2 - part3 - part4;

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Jakub Laznovsky
Jakub Laznovsky 2021년 5월 19일
Hi guys, can you please help me with conversion this piece of code to the mathematical equation?
It i a simple 3D mask proceeding the image, and searching for adjoining number one and number two. Thank you in advance.
Code:
m1=[0 0 0; 0 1 0; 0 0 0];
m2=[0 1 0; 1 1 1; 0 1 0];
mask=zeros(3,3,3);
mask(:,:,1)=m1;mask(:,:,2)=m2;mask(:,:,3)=m1;
for i=2:size(image,1)-1
for j=2:size(image,2)-1
for k=2:size(image,3)-1
help_var=image(i-1:i+1,j-1:j+1,k-1:k+1);
if sum(unique(help_var(mask==1)))==3
new_image(i,j,k)=3; %marks adjoining pixel with number 3
end
end
end
end
  댓글 수: 4
Jakub
Jakub 2021년 5월 22일
Thanks a lot!

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Adhin Abhi
Adhin Abhi 2022년 1월 4일
(λlog vmax−log vmin) /(vmax−vmin )
  댓글 수: 1
Walter Roberson
Walter Roberson 2022년 1월 4일
(lambda .* log(vmax) - log(vmin)) ./ (vmax - vmin)

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Lukasz Sarnacki
Lukasz Sarnacki 2022년 8월 17일
Please help
  댓글 수: 5
Walter Roberson
Walter Roberson 2022년 8월 18일
syms n N integer
syms A(x,y) B(x,y) phi(x,y)
Pi = sym(pi)
Pi = 
π
I(n,x,y) = A(x, y) + B(x,y) * cos(phi(x,y) - 2*Pi*n/N)
I(n, x, y) = 
numerator = simplify(symsum(I(n, x, y) .* sin(2*Pi*n/N), n, 0, N-1))
numerator = 
denominator = simplify(symsum(I(n, x, y) .* cos(2*Pi*n/N), n, 0, N-1))
denominator = 
eqn = phi(x,y) == atan(numerator ./ denominator)
eqn = 
simplify(eqn)
ans = 

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