How do I separate date and time of a raw date?
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>> a = untitled.startDate(1:10)
a =
10×1 categorical array
2013-07-10 00:01:00.0
2013-07-17 00:01:00.0
2013-06-29 00:01:00.0
2013-07-17 00:01:00.0
2013-05-11 00:01:00.0
2013-05-31 00:01:00.0
2013-06-06 00:01:00.0
2013-08-31 00:01:00.0
2013-05-21 00:01:00.0
2013-08-06 00:01:00.0
>> a.Format = 'dd-MMM-yyyy'
Error using categorical/subsasgn (line 87)
Attempt to assign field of non-structure array.
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Ahmet Cecen
2018년 3월 30일
편집: Ahmet Cecen
2018년 3월 30일
arrayfun(@(x) strsplit(x,' '),string(a),'UniformOutput',false)
string(a) - this makes the data easily process-able, converts to a string array.
@(x) strsplit(x,' ') - this is a function that splits each string into parts whenever a space(' ') is located(which works for your case)
arrayfun - applies the above function to each "row" in the string array.
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Peter Perkins
2018년 4월 2일
Don't do any of that.
You've read the timestamps in as datetimes. Don't fight that. Assuming you have a table T:
T.StartTime = timeofday(T.StartDate);
T.StartDate = dateshift(T.StartDate,'start','day);
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Steph
2019년 2월 24일
I missteated my problem I think, I am doing regressions on the data that is collected on each of the specific days. Not on the dates or days themselves
Walter Roberson
2019년 2월 24일
Then you do not need to convert the dates + times or datetime objects to numeric. What you need to do is be able to group your data based upon date. You should have a look at splitapply() -- or convert the table to a timetable() object and use retime()
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