Can someone please help me with a loop issue.

I am trying to write a simple strain loop such that the first strain value E_1=0, and subsequent values follow with an increment of 0.02 that is delta strain between each step is 0.02, the loop I wrote is as follows:
for i=2:10
E_1=0;
E_(i)=E_(i-1)+0.02
end
but this does not work for some reason it gives an error that E_ is an undefined function. Can anyone please help me with this very simple problem.

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Stephen23
Stephen23 2018년 3월 21일
편집: Stephen23 2018년 3월 21일
E_1=0;
defines a variable named exactly E_1. Then you try to access the first element of a variable named E_ which clearly does not exist at that point. Note that E_1 is not how indexing works: it does not treat the 1 as an index, it is part of the name!
Thank you for your reply, I have understood the issue I wrote for i=2:11 E(1)=0; E(i)=E(i-1)+0.02; end and it worked :)

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David Fletcher
David Fletcher 2018년 3월 21일
편집: David Fletcher 2018년 3월 21일

0 개 추천

E_=0:0.02:0.2
Values are indexed as E_(1), E_(2) and so on

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Thank you for your reply, I thought of writing this in this form as well, but I want the values to be displayed as E_1=0, E_2=0.02, E_3=0.04... In the way you wrote the matrix E_ is formed with all values in 1st column
It's up to you, but I really wouldn't advise you to separate your variables like that - it's makes processing your data much, much more difficult. The code you've posted won't work in that way anyway, and I'm not in the habit of propagating bad habits, so I'll leave it up to you to amend it yourself if you really want to make them all separate variables.
James Tursa
James Tursa 2018년 3월 21일
"... but I want the values to be displayed as E_1=0, E_2=0.02, E_3=0.04... "
Please don't name variables this way! There's lots of posts on this site telling you why, but just don't do it! Keep the numbers as a vector and use indexing, or if you really need separate variables for some reason (that you haven't told us), try a cell array E_{1}, E_{2}, etc.
Thank you, will avoid it from now on, forgive me I am new to this.

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