Divide a matrix with an array along a specific dimension

A=rand(10,20,30);
B=[1:30];

I want to divide A with B along the third dimension. I got the required result using loop.

for ii=1:30
   C(:,:,ii)=A(:,:,ii)/B(ii); 
end

But is there any pre-defined function which does the same operation, which takes the dimension as a input along which we want to divide a matrix.

Answer 1

[Stephen23]

Once you make the sizes compatible you can do this using standard methods without any loop. Use permute or reshape to get the correct size of B. For example In R2016b and later a standard rdivide will do this:

A ./ reshape(B,1,1,[])

or for earlier versions use bsxfun:

bsxfun(@rdivide,A,reshape(B,1,1,[]))

[ANKUR KUMAR]

Thank you, Sir.

Answer 2

[Akira Agata]

How about using arrayfun ?

C = arrayfun(@(k) A(:,:,k)./B(k), 1:30,'UniformOutput',false);
C = cat(3,C{:});

[Beata Opacka]

This works amazing!!!