Shift left and replace the LSB bit?

I want to replace the LSB bit with logical 1 or 0. I have 10/8 array. It is replacing the LSB bit only for the first row. But for the second row onwards it is not working.

01111111

11111110

00000010

00001010

00100110

10000010

11111110

00000010

00001011

00101100

Every row should be shifted left and replaced with logic 0 or 1 which is stored in some variable let it be 'kj'. The code I written was

            ex=bu(i,:)  % here bu is char array
            z = [ex(2:end), '0']    
            kj=num2str(out);  %out is logical 1 or 0
            z(i,8)=kj;
            c=z(i,:)

getting c for the first row correctly but from second row onwards it is giving a single bit like 0 or 1.

Answer 1

[James Tursa]

bu = your char array
result = bu(:,2:end);
result(:,end+1) = new_bit_char;

E.g.,

>> bu = char((rand(5,8)<0.5)+'0')  % some random sample data
bu =
10110111
01000111
11101100
01100101
00111111
>> new_bit_char = '1'
new_bit_char =
1
>> result = bu(:,2:end)
result =
0110111
1000111
1101100
1100101
0111111
>> result(:,end+1) = new_bit_char
result =
01101111
10001111
11011001
11001011
01111111

[RAKESH REDDY]

Thank you very much