Hi i have a 3d matrix
resultA=zeros(221,5,1000000);
A1= 0 + (1-0).*rand(221,1);
X11= A*A1;
P= zeros(221,1);
P(:)= X11(:)/max(X11);
D1= 0 + (1-0).*rand(221,1);
to store values
i=1:1000000
resultA(:,1,i)=A1; % 221X1 random values for every iteration
resultA(:,2,i)=D1; % 221X1 random values for every iteration
resultA(:,3,i)=P; % 221X1 calculated values every iteration
resultA(1,4,i)=UtilityD; % 1 calculated values every iteration based on A1 nad D1
resultA(1,5,i)=UtilityA; % 1 calculated values every iteration based on A1 nad D1
My requirement is after completing 1000000 iterations I want to find the same A1 and D1 vectors that will gives maximum utility for both utilityD and utilityA.

댓글 수: 2

Walter Roberson
Walter Roberson 2018년 3월 1일
If there were 3 candidates, (4,2), (3,3), (0,6), then which of these would be considered to be the maximum utility for both entries?
It may have multiple solutions and if there are multiple solutions it should show the multiple utilities with their corresponding A1 and D1.

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

도움말 센터File Exchange에서 Octave에 대해 자세히 알아보기

질문:

2018년 3월 1일

댓글:

2018년 3월 1일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by