Why there is a difference between the dct computed by the MATLAB dct function and one computed by dct matrix multiplication?
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![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/170771/image.png)
The result is different, though both methods give inverse transform correctly.
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David Goodmanson
2018년 2월 26일
편집: David Goodmanson
2018년 2월 26일
Hi Mohsin,
x needs to be a column vector as you did, but you don't need to take the transpose of dctmtx:
x = 1:8
y1 = dct(x')
y2 = dctmtx(8)*x'
y1 - y2
x1 = idct(y1)
x2 = dctmtx(8)\y2
Same results, out and back.
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