Syntax for a relational statement within a loop

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Yunus Harmanci
Yunus Harmanci 2012년 5월 15일
Hello everyone,
I would consider myself to be an "intermediate" level matlab user, however I have come across a problem that drives me absolute mad!!
I have a formula that has two different formulations(depends on some parameters) and this formula is within a loop. I do not know how to write the statement and the loop index together.. here is the part of the code.
Kind regards,
Yunus
for dd=1:size((F_LE),2)-1
#some other stuff that works
%This is the general formulation
del_F_Lk_BL(dd) = sqrt(bf^2*tau_L1*s_L0*Ef*t + (F_LE(dd))^2) - F_LE(dd);
%This one is going to be the formulation only if *F_LE(dd) <= F_Lk_BL_D* and should somehow be written in the left hand side of the below formula:
del_F_Lk_BL(dd) = del_F_Lk_BL_G - (del_F_Lk_BL_G - del_F_Lk_BL_D)/del_F_Lk_BL_D*F_LE(dd);
end
Again, than you very much!!

답변 (1개)

Walter Roberson
Walter Roberson 2012년 5월 15일
You do not need anything fancy at all, as you are looping over individual dd.
for dd=1:size((F_LE),2)-1
#some other stuff that works
if F_LE(dd) <= F_Lk_BL_D
del_F_Lk_BL(dd) = del_F_Lk_BL_G - (del_F_Lk_BL_G - del_F_Lk_BL_D)/del_F_Lk_BL_D*F_LE(dd);
else
del_F_Lk_BL(dd) = sqrt(bf^2*tau_L1*s_L0*Ef*t + (F_LE(dd))^2) - F_LE(dd);
end
end
  댓글 수: 1
Yunus Harmanci
Yunus Harmanci 2012년 5월 15일
Thank you very much Walter, apparently I was too posh to do a basic if statement. :) That solved my problem, thanks!

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