Error with ode45 when using a decreasing x value: more non-singleton rhs dimensions than non-singleton subscripts

조회 수: 3 (최근 30일)
I am working on a problem in which I use ode45 to estimate an equation as x goes from 8 to .0, using 78 steps of the size .1. Y is increasing as x decreases.
The equation is: function f=fun2(t,y) f=('-(sqrt(100-t^2)/(t))')
I used a linspace to hold the step values: p=linspace(8,0.2,78)
With the initial y value to be 6, I set it all up as:
[x,y]=ode45('fun2',p,6)
However, I am consistently getting this error:
"Assignment has more non-singleton rhs dimensions than non-singleton subscripts
Error in ode45 (line 184) k_(:,1)=feval(FUN,t,x); % first stage"
What am I doing wrong, and how can I fix this? I am quite new to Matlab, and am not sure what to do.

채택된 답변

Torsten
Torsten 2018년 2월 26일
편집: Torsten 2018년 2월 26일
function main
tspan=linspace(8,0.2,78);
y0=6;
[t,y]=ode45(@fun2,tspan,y0)
function f = fun2(t,y)
f=-sqrt(100-t^2)/t;
end
Best wishes
Torsten.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Ordinary Differential Equations에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by