How do I run increments of numbers through a function?

I would like to know how to run numerous numbers through a function. For example, I would like to start at number 95 and decrease by increments of .1.

so 95.0000, 94.9000, 94.8000, 94.7000, 94.6000, 94.5000, 94.4000....... and so on...

I want to run these numbers to the attached function "m.m" file until the output generated is 35

Answer 1

[Eric Tao]

Use MATLAB colon expression, and you don't need for-loop anymore.

Run:

a = [95:-0.1:35]';

you will get the result.

[Stephen23]

As you are not concatenating anything use parentheses, not square brackets:

a = (95:-0.1:35)';

Answer 2

[Walter Roberson]

L = 95;
while true
  output = m(L);
  fprintf('For L = %f, output = %g\n', L, output);
  if output == 35
     break;
  end
  L = L - 0.1;
end

However.... there is no guarantee that m() will ever give an output of exactly 35. http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F

If the task were to find the L such that m(L) == 35, then you would not proceed sequentially: you would use fzero or fsolve:

fzero(@(L) m(L)-35, 95)