fmincon, find integer values as optimal values

조회 수: 4 (최근 30일)
Mohamed Musni
Mohamed Musni 2018년 2월 1일
댓글: Mohamed Musni 2018년 2월 1일
f =@(fr)(50*fr(1)^2 + 100)/fr(1) + (175*fr(2)^2 + 150)/fr(2) + (160*fr(3)^2 + 250)/fr(3)
lb = [0,0,0];
ub = [5,5,5];
A = [];
b = [];
Aeq = [];
beq = [];
fr0 = [1,1,1];
fr = fmincon(f,fr0,A,b,Aeq,beq,lb,ub)
output:
f =
function_handle with value:
@(fr)(50*fr(1)^2+100)/fr(1)+(175*fr(2)^2+150)/fr(2)+(160*fr(3)^2+250)/fr(3)
Local minimum possible. Constraints satisfied.
fmincon stopped because the size of the current step is less than
the default value of the step size tolerance and constraints are
satisfied to within the default value of the constraint tolerance.
<stopping criteria details>
fr =
1.4142 0.9258 1.2500
I want to find positive integer values rather than decimal values for my variables. is there any way to include this condition with fmincon? any help will be highly appreciated. thank you

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Sean de Wolski
Sean de Wolski 2018년 2월 1일
편집: Sean de Wolski 2018년 2월 1일
fmincon is not designed to deal with integer x values. You should try ga() which has an IntCon option or patternsearch() with a round() on the input values.
Of course for a small problem like this there are only 216 unique combinations of x so you could easily brute force it.
[rr,cc,pp] = ndgrid(0:5);
v = (50*rr.^2 + 100)./rr + (175*cc.^2 + 150)./cc + (160*pp.^2 + 250)./pp;
[val, idx] = min(v(:));
[rr(idx) cc(idx) pp(idx)]
  댓글 수: 1
Mohamed Musni
Mohamed Musni 2018년 2월 1일
thank you. I found tutorial with ga() and abled to get answer with integer values. have a nice day

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