How to use for loop rather than nesting if loop

조회 수: 1 (최근 30일)
Alex
Alex 2018년 1월 27일
댓글: Alex 2018년 1월 28일
I want to use this code to subtract one value from each number in the histogram when all have been selected to find the new number with zero counts. This code worked (since there are two if loops with one nested) for the first two times 1 is subtracted from cdiff, but then returns the error 'Unbalanced or unexpected parenthesis or bracket.' : %check if Cdiff is empty:
if isempty(C_diff)
fprintf('C_diff is empty (all numbers have drawn once) \n');
cdiff_counts= counts - 1;%cdiff_data_vector = reshape(data,[9,numel(data)]);
C_diff = find(cdiff_counts==0);%return vector of values with 0
fprintf('By subtracting 1 count for all numbers, the new C_diff is %d\n', C_diff);
if isempty(C_diff)
fprintf('C_diff is empty (all numbers have drawn once) \n');
cdiff_counts= cdiff_counts - 1;%cdiff_data_vector = reshape(data,[9,numel(data)]);
C_diff = find(cdiff_counts==0);%return vector of values with 0
fprintf('By subtracting 1 count for all numbers, the new C_diff is %d\n', C_diff);
end
else
fprintf('C_diff is %d\n', C_diff);%
end
Replacing the first 'if' with 'for' returns 'Unbalanced or unexpected parenthesis or bracket.'
How can I get this to occur until C_diff is no longer an empty array?
if isempty(C_diff)
fprintf('C_diff is empty (all numbers have drawn once) \n');
cdiff_counts= counts - 1;%cdiff_data_vector = reshape(data,[9,numel(data)]);
C_diff = find(cdiff_counts==0);%return vector of values with 0
fprintf('By subtracting 1 count for all numbers, the new C_diff is %d\n', C_diff);
else
fprintf('C_diff is %d\n', C_diff);%
end
Best regards,
Alex
  댓글 수: 2
Jan
Jan 2018년 1월 27일
There are no "if loops" in any programming language.
Alex
Alex 2018년 1월 27일
ok, "if statement"?

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채택된 답변

Jan
Jan 2018년 1월 27일
편집: Jan 2018년 1월 27일
while isempty(C_diff)
cdiff_counts = counts - 1;
C_diff = find(cdiff_counts == 0);
end
It looks like C_diff contains positive values initially, maybe only integers. Then this is more efficient:
minValue = min(counts); % [EDITED]
C_diff = find(C_diff = minValue);
  댓글 수: 3
Jan
Jan 2018년 1월 27일
I had a typo in the min() call. I assume, it is much cheaper. If you provide some meaningful inputs data and the wanted result, I could even test my suggestions.
Alex
Alex 2018년 1월 28일
Thank you! I will keep that in mind for future questions. It is not necessary, but if you are interested, here is the "counts" data for numbers 1:1:49. The number 32 should be returned.

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