Finding longest consecutive numbers in array
조회 수: 42 (최근 30일)
이전 댓글 표시
Hello everyone,
This is somewhat of a silly question but I can't seem to figure it out. If I have an array of numbers what I want is to find the location of my longest consecutive numbers for example:
my arrary = [ 1999 2000 2001 2003 2004 2005 2006 2007];
I want my output to be = [ 4 5 6 7 8]; because that's the location of my longest consecutive numbers (2003-2007). I tried to find where difference is equal to 1 but then the result is [1 1 1 0 1 1 1 1] , it doesn't take the position of the last number which is 2007 here and even if I fix that problem also I'd still have to find the locations for the longest consecutive one's for the second scenario.
I could use some help in this,
Thank You!!!
댓글 수: 0
채택된 답변
Stephen23
2018년 1월 27일
편집: Stephen23
2025년 10월 24일 14:45
V = [1999,2000,2001,2003,2004,2005,2006,2007];
D = diff([0;diff(V(:))==1;0]);
B = find(D>0);
E = find(D<0);
[~,idx] = max(E-B);
idy = B(idx):E(idx)
댓글 수: 4
Stephen23
2025년 10월 24일 14:44
편집: Stephen23
2025년 10월 24일 14:49
@Martina: well spotted! I made a few changes, please check it!
longestConsecutive([2001,2002,2003,2004,2005,2006,2007,2009,2010]) % 1:7
longestConsecutive([1999,2001,2003,2004,2005,2006,2007,2009,2010]) % 3:7
longestConsecutive([1999,2001,2003,2004,2005,2006,2007,2008,2009]) % 3:9
longestConsecutive([2001,2002,2003,2004,2005,2006,2007,2008,2009]) % 1:9
longestConsecutive([2001,2003,2005,2007]) % none
function idy = longestConsecutive(inp)
D = diff([0;diff(inp(:))==1;0]);
B = find(D>0);
E = find(D<0);
[~,idx] = max(E-B);
idy = B(idx):E(idx);
end
As an alternative you could use something from FEX, for example
on the DIFF() of the vector.
추가 답변 (1개)
참고 항목
카테고리
Help Center 및 File Exchange에서 MATLAB Report Generator에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!