replace element in the vector without using loops or if statement

using a logical vector and a single line of code (3 total lines if you count the “function” line and the “end” line). Your function should not have any loops or if statements in it. (You should assume the input is a row vector.)

here is the given code:

function [ y ] = nottwo( v )
y = [];
for i = 1:length(v)
    if v(i)~= 2
    y = [y, 0];
    else
    y = [y, 10];
   end
end

Answer 1

[Star Strider]

It is difficult to help without giving away the solution.

To use a logical vector to address the array, see what this example code is doing:

v = randi(9, 1, 20)
LogicalIndex = v ~= 2

See the documentation on Matrix Indexing (link) for a full discussion.

[Walter Roberson]

Hint: logical vectors can be multiplied by a constant such as 10.

[siemcheng ngor]

i tried it but it still give me 1

[Star Strider]

Please see the documentation on Matrix Indexing I linked to.