Index exceeds matrix dimensions

Dear All I am trying to solve equation but i am getting error code is:
M=100;
r=0.8;
alpha=0.45;
beta=0.75;
gama=0.1;
d=0.004;
h=0.4;
n=100;
c(1)=1580;
c0=1500;
lembda=150;
delT=1;
x(1)=2;
a(1)=1000;
p(1)=100;
q(1)=0.8;
for t=1:20
q(t)=0.8;
xx=t+1;
x(xx)=x(t)+delT*(alpha+beta*log(a(t))+gama*x(t))*(M-x(t))*exp(-d*p(t))*exp(h*q(t))
%disp(x(t));
x(xx)
lembda(xx)=lembda(t)*(r*lembda(t)-exp(-d*p(t))*exp(h*q(t)*(gama*M-alpha-beta*log(a(t))-2*gama*x(t))*(p(t)-c(t)+lembda(t))+n*q(t)^x(t)-1*log(q(t))...
*(alpha+beta*log(a(t))+gama*x(t))*(M-x(t))*exp(-d*p(t))*exp(h*q(t))))
% disp('lembda(t+1)');
lembda(xx)
c(t)=n*q(t)^x(t)-1+c0
% disp('c(t)');
c(t)
p(t)=c(t)-lembda(t)+1/alpha
% disp('p(t)');
p(t)
a(t)=(p(t)-c(t)+lembda(t))*beta*(M-x(t))*exp(-d*p(t))*exp(h*q(t))
%disp('a(t)');
a(t)
end
when i am running this but i am getting error "??? Index exceeds matrix dimensions." actually i want the value of x(1) to x(20), lembda(1) to lembda(20), p(1) to p(20), c(1) to c(20),a(1) to a(20) please help me Thank you.

답변 (1개)

Andreas Goser
Andreas Goser 2012년 5월 8일

0 개 추천

When I run this code in this line
x(xx)=x(t)+delT*(alpha+beta*log(a(t))+gama*x(t))*(M-x(t))*exp(-d*p(t))*exp(h*q(t))
because in the second time the loop gets executed, it want to have a(2), but a is still 1x1.
Why THAT is it is up to you, as I don't know what you want to achive.

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도움말 센터File Exchange에서 Matrices and Arrays에 대해 자세히 알아보기

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2012년 5월 8일

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