Index exceeds matrix dimensions
이전 댓글 표시
Dear All I am trying to solve equation but i am getting error code is:
M=100;
r=0.8;
alpha=0.45;
beta=0.75;
gama=0.1;
d=0.004;
h=0.4;
n=100;
c(1)=1580;
c0=1500;
lembda=150;
delT=1;
x(1)=2;
a(1)=1000;
p(1)=100;
q(1)=0.8;
for t=1:20
q(t)=0.8;
xx=t+1;
x(xx)=x(t)+delT*(alpha+beta*log(a(t))+gama*x(t))*(M-x(t))*exp(-d*p(t))*exp(h*q(t))
%disp(x(t));
x(xx)
lembda(xx)=lembda(t)*(r*lembda(t)-exp(-d*p(t))*exp(h*q(t)*(gama*M-alpha-beta*log(a(t))-2*gama*x(t))*(p(t)-c(t)+lembda(t))+n*q(t)^x(t)-1*log(q(t))...
*(alpha+beta*log(a(t))+gama*x(t))*(M-x(t))*exp(-d*p(t))*exp(h*q(t))))
% disp('lembda(t+1)');
lembda(xx)
c(t)=n*q(t)^x(t)-1+c0
% disp('c(t)');
c(t)
p(t)=c(t)-lembda(t)+1/alpha
% disp('p(t)');
p(t)
a(t)=(p(t)-c(t)+lembda(t))*beta*(M-x(t))*exp(-d*p(t))*exp(h*q(t))
%disp('a(t)');
a(t)
end
when i am running this but i am getting error "??? Index exceeds matrix dimensions." actually i want the value of x(1) to x(20), lembda(1) to lembda(20), p(1) to p(20), c(1) to c(20),a(1) to a(20) please help me Thank you.
답변 (1개)
Andreas Goser
2012년 5월 8일
When I run this code in this line
x(xx)=x(t)+delT*(alpha+beta*log(a(t))+gama*x(t))*(M-x(t))*exp(-d*p(t))*exp(h*q(t))
because in the second time the loop gets executed, it want to have a(2), but a is still 1x1.
Why THAT is it is up to you, as I don't know what you want to achive.
카테고리
도움말 센터 및 File Exchange에서 Matrices and Arrays에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!