problem with vectors and dimensions

Good evening! I tried to solve this algorithm in script file

and Cn from this Table

and p is we will neglect it . I will use this vector for (a) (just for test )

a=[1 -0.2 3.005 -39608 - 0.0985 1.2311];

and at the end I must to get this result (note; RD=R)

I used this Matlab code

    % code
a=[1 -0.2 3.005 -39608 - 0.0985 1.2311];
n=length(a);
Ck = [[-16 0 20 0 -5 0] [8 0 -8 0 1] [-4 0 3 0] [2 0 -1] [-1 0]];  %%%Cn
switch n

    case 1
               R=0;
        w=[1 7 12 16 19 0];
        p=[6 11 15 18 20 0];
       for i=1:n+1 ;
           R=R+(a(i)*Ck(w(i):p(i))); 
       end
    case 2
               R=0;
        w=[1 7 12 16 19 0];
        p=[6 11 15 18 20 0];
       for i=1:n+1 ;
           R=R+(a(i)*Ck(w(i):p(i))); 
       end
    case 3
               R=0;
        w=[1 7 12 16 19 0];
        p=[6 11 15 18 20 0];
       for i=1:n+1 ;
           R=R+(a(i)*Ck(w(i):p(i))); 
       end
    case 4
               R=0;
        w=[1 7 12 16 19 0];
        p=[6 11 15 18 20 0];
       for i=1:n+1 ;
           R=R+(a(i)*Ck(w(i):p(i))); 
       end
    case 5
        R=0;
        w=[1 7 12 16 19 0];
        p=[6 11 15 18 20 0];
       for i=1:n+1 ;
           R=R+(a(i)*Ck(w(i):p(i)));
       end
    otherwise
        disp('high order')
end

and i got error because the dimensions are different between the vectors and i used {switch .. case } because in the future i want to Enter different values of (a) and with different lengths (I want to build algorithm working with any values of (a)) .

please if anyone can help me to find the another solution (but without use any function from symbolic toolbox functions because my target is solve it without symbolic math toolbox ) Thank you

Answer 1

[ANKUR KUMAR]

You are getting an error in this line

R=R+(a(i)*Ck(w(i):p(i)));

The dimension of R is 1*6 and dimension of (a(i)*Ck(w(i):p(i))) is 1*5 How can you add the matrices of different dimension.

[laith ismail]

thank you for replay the dimension of Ck is changing with every step because if you see the Eq above related with Ck its depend on the number of K or n (because these are same ) and i know there are problems with the dimension but how can i solve it ? this the question and if you have some advise please tell me .

[ANKUR KUMAR]

What is the purpose of adding these R. There may be some logic behind this. Instead of adding, you can store every R in call format by using R{i}.

[Walter Roberson]

Pad the shorter one with leading zeros before doing the addition.