- [0, range-1] if range is a positive integer
- [range+1, 0] if range is a negative integer
- Between min and max, inclusive, if range = [min,max] or [max,min]
how can replace randi instead randint?
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hi ;i have a question please help me , i want to replace randi instead randint in ofdm_basic code in r2017a , but i dont know how i must do it . please answer and help me . this is that line :
X=randint(1,Nused*Nframe,M); % bit: integer vector
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채택된 답변
Jan
2018년 1월 2일
편집: Jan
2018년 1월 2일
Do you mean randint from the Communications Toolbox or is this from Octave code?
I assume, for both the answer is the same: It depends on what M is.
% X = randint(1, Nused*Nframe, M)
if length(M) == 1
if M > 0
Range = [0, M-1];
else
Range = [M+1, 0];
end
else
Range = [min(M), max(M)];
end
X = randi(Range, 1, Nused*Nframe);
I do not have this toolbox, but I guess that you should find something like this, if you look into the randint function:
edit randint
추가 답변 (5개)
Geoff Hayes
2018년 1월 2일
mohamad - which ofdm_basic code are you referring to? Is this something found on the MATLAB FileExchange or something else? From Communications System Toolbox Release Notes, it looks like randint has been removed from the Communications System Toolbox and is to be replaced with randi.
If we assume that the code
X=randint(1,Nused*Nframe,M)
creates a 1x(Nused*Nframe) matrix with integers in the interval [0,M-1], then we can replace the above with
X = randi(M, 1, Nused*Nframe) - 1;
I think that will work...
댓글 수: 4
Mochan Yang
2019년 7월 22일
bitstream=randi(2,1,N)-1
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Walter Roberson
2019년 7월 22일
bitstream = randi([0 1], 1, N);
or
bitstream = rand(1,N) >= 0.5;
khalil nasri
2021년 3월 6일
randn( )>0;
댓글 수: 1
Walter Roberson
2021년 3월 6일
Normal distribution has peak probability at 0 exactly. Does testing for strict greater than give 50% exactly?
HONG CHENG
2022년 4월 28일
you can look at this link
Specifically
You just need to change the order of paramters
a=randint(3,4,[1,4]);
a=randi([1,4],3,4);
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