how can replace randi instead randint?
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hi ;i have a question please help me , i want to replace randi instead randint in ofdm_basic code in r2017a , but i dont know how i must do it . please answer and help me . this is that line :
X=randint(1,Nused*Nframe,M); % bit: integer vector
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Geoff Hayes
2018년 1월 2일
mohamad - which ofdm_basic code are you referring to? Is this something found on the MATLAB FileExchange or something else? From Communications System Toolbox Release Notes, it looks like randint has been removed from the Communications System Toolbox and is to be replaced with randi.
If we assume that the code
X=randint(1,Nused*Nframe,M)
creates a 1x(Nused*Nframe) matrix with integers in the interval [0,M-1], then we can replace the above with
X = randi(M, 1, Nused*Nframe) - 1;
I think that will work...
댓글 수: 4
mohamad gholami
2018년 1월 2일
편집: Geoff Hayes
2018년 1월 2일
Geoff Hayes
2018년 1월 2일
ok, so try replacing with the line
X = randi(M, 1, Nused*Nframe) - 1;
I subtract one since randi will generate integers from the interval [1,M] and not the [0,M-1] that randint seems to be using.
mohamad gholami
2018년 1월 2일
Geoff Hayes
2018년 1월 3일
Mochan Yang
2019년 7월 22일
0 개 추천
bitstream=randi(2,1,N)-1
댓글 수: 1
Walter Roberson
2019년 7월 22일
bitstream = randi([0 1], 1, N);
or
bitstream = rand(1,N) >= 0.5;
Yusuf lamah
2020년 3월 22일
0 개 추천
thank you very much
khalil nasri
2021년 3월 6일
0 개 추천
randn( )>0;
댓글 수: 1
Walter Roberson
2021년 3월 6일
Normal distribution has peak probability at 0 exactly. Does testing for strict greater than give 50% exactly?
HONG CHENG
2022년 4월 28일
you can look at this link
Specifically
You just need to change the order of paramters
a=randint(3,4,[1,4]);
a=randi([1,4],3,4);
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