Why ParFor does not work for this?
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It is a really simple manipulation. I want to replace some lines of the matrix with zeros.
A=rand(20,20);
for j=1:1:4
A(4*j+1,:)=zeros;
end
When I replace for with parfor I get a classification error. But the results of the manipulation is independent from each other. I don't understand why.
Thank you Erdem
답변 (1개)
Namnendra
2022년 6월 19일
0 개 추천
All variables referenced at the top level of the parfor must be resolved and classified. Go through the following link to know more :-
You can try putting the body of perfor loop into a function and calling the function from the loop.
I hope this helps.
카테고리
도움말 센터 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
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