Why ParFor does not work for this?

It is a really simple manipulation. I want to replace some lines of the matrix with zeros.
A=rand(20,20);
for j=1:1:4
A(4*j+1,:)=zeros;
end
When I replace for with parfor I get a classification error. But the results of the manipulation is independent from each other. I don't understand why.
Thank you Erdem

답변 (1개)

Namnendra
Namnendra 2022년 6월 19일

0 개 추천

All variables referenced at the top level of the parfor must be resolved and classified. Go through the following link to know more :-
You can try putting the body of perfor loop into a function and calling the function from the loop.
I hope this helps.

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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질문:

2017년 12월 27일

답변:

2022년 6월 19일

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