magic code from C++ language to Matlab?

조회 수: 29 (최근 30일)
sajjad esmaili
sajjad esmaili 2017년 12월 22일
댓글: sajjad esmaili 2017년 12월 22일
Hi, I've typed this code in C and now I want to convert to MATLAB code. Thank you for helping me.
#include "stdafx.h"
#include <vector>
using namespace std;
void OddMagicSquare(vector<vector<int> > &matrix, int n);
void DoublyEvenMagicSquare(vector<vector<int> > &matrix, int n);
void SinglyEvenMagicSquare(vector<vector<int> > &matrix, int n);
void MagicSquare(vector<vector<int> > &matrix, int n);
void PrintMagicSquare(vector<vector<int> > &matrix, int n);
int main(int argc, char* argv[])
{
int n;
printf("Enter order of square: ");
scanf("%d", &n);
vector<vector<int> > matrix(n, vector<int> (n, 0));
if (n<3)
{
printf("\nError: n must be greater than 2\n\n");
return -1;
}
MagicSquare(matrix, n);
//Print results
PrintMagicSquare(matrix, n);
return 0;
}
void MagicSquare(vector<vector<int> > &matrix,int n)
{
if (n%2==1) //n is Odd
OddMagicSquare(matrix, n);
else //n is even
if (n%4==0) //doubly even order
DoublyEvenMagicSquare(matrix, n);
else //singly even order
SinglyEvenMagicSquare(matrix, n);
}
void OddMagicSquare(vector<vector<int> > &matrix, int n)
{
int nsqr = n * n;
int i=0, j=n/2; // start position
for (int k=1; k<=nsqr; ++k)
{
matrix[i][j] = k;
i--;
j++;
if (k%n == 0)
{
i += 2;
--j;
}
else
{
if (j==n)
j -= n;
else if (i<0)
i += n;
}
}
}
void DoublyEvenMagicSquare(vector<vector<int> > &matrix, int n)
{
vector<vector<int> > I(n, vector<int> (n, 0));
vector<vector<int> > J(n, vector<int> (n, 0));
int i, j;
//prepare I, J
int index=1;
for (i=0; i<n; i++)
for (j=0; j<n; j++)
{
I[i][j]=((i+1)%4)/2;
J[j][i]=((i+1)%4)/2;
matrix[i][j]=index;
index++;
}
for (i=0; i<n; i++)
for (j=0; j<n; j++)
{
if (I[i][j]==J[i][j])
matrix[i][j]=n*n+1-matrix[i][j];
}
}
void SinglyEvenMagicSquare(vector<vector<int> > &matrix, int n)
{
int p=n/2;
vector<vector<int> > M(p, vector<int> (p, 0));
MagicSquare(M, p);
int i, j, k;
for (i=0; i<p; i++)
for (j=0; j<p; j++)
{
matrix[i][j]=M[i][j];
matrix[i+p][j]=M[i][j]+3*p*p;
matrix[i][j+p]=M[i][j]+2*p*p;
matrix[i+p][j+p]=M[i][j]+p*p;
}
if (n==2)
return;
vector<int> I(p, 0);
vector<int> J;
for (i=0; i<p; i++)
I[i]=i+1;
k=(n-2)/4;
for (i=1; i<=k; i++)
J.push_back(i);
for (i=n-k+2; i<=n; i++)
J.push_back(i);
int temp;
for (i=1; i<=p; i++)
for (j=1; j<=J.size(); j++)
{
temp=matrix[i-1][J[j-1]-1];
matrix[i-1][J[j-1]-1]=matrix[i+p-1][J[j-1]-1];
matrix[i+p-1][J[j-1]-1]=temp;
}
//j=1, i
//i=k+1, k+1+p
i=k;
j=0;
temp=matrix[i][j]; matrix[i][j]=matrix[i+p][j]; matrix[i+p][j]=temp;
j=i;
temp=matrix[i+p][j]; matrix[i+p][j]=matrix[i][j]; matrix[i][j]=temp;
}
void PrintMagicSquare(vector<vector<int> > &matrix, int n)
{
for (int i=0; i<n; i++)
{
for (int j=0; j<n; j++)
printf(" %3d", matrix[i][j]);
printf("\n");
}
printf("\n\n");
}

답변 (1개)

Walter Roberson
Walter Roberson 2017년 12월 22일
The equivalent code is:
n = input('Enter order of square: ');
magic(n)
  댓글 수: 1
sajjad esmaili
sajjad esmaili 2017년 12월 22일
I want to write a magic matrix function

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Logical에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by