I have a timestamp like "x2017_12_1816:00_00". It is in a format "xyyyy_mm_dd_hh:mm:ss". However, matlab will not allow this to convert to a date vector since it's not in an acceptable format. I've been able to convert it to a date format by using the code below, where structFields is a structure containing the unconverted timestamps. As you might imagine, this method takes a long time. I've tried to accomplish the same effect by first converting the timestamps to a number in the format "yyyymmddhhmmss", but have yet to come up with a more efficient algorithm. Any suggestions?
if true
% code
structEdit1 = cellfun(@(x) replaceBetween(x,13,15,':','Boundaries','exclusive'),structFields,'UniformOutput',false);
structEdit2 = cellfun(@(x) replaceBetween(x,16,18,':','Boundaries','exclusive'),structEdit1,'UniformOutput',false);
structEdit3 = cellfun(@(x) strrep(x(),'_','-'),structEdit2,'UniformOutput',false);
structEdit4 = cellfun(@(x) insertAfter(x,11,' '),structEdit3,'UniformOutput',false);
structEdit5 = cellfun(@(x) erase(x,'x'),structEdit4,'UniformOutput',false);
end

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Walter Roberson
Walter Roberson 2017년 12월 19일
편집: Walter Roberson 2017년 12월 19일

1 개 추천

datetime('x2017_12_1816:00_00', 'InputFormat', '''x''yyyy_MM_ddHH:mm_ss', 'Format', 'yyyyMMddHHmmss')
The tricks here:
  • datetime uses MM for month and mm for minutes
  • datetime uses HH for 24 hour hour
  • any alphabetic character that is intended to be used literally must be put inside '' inside the string.
>> disp('''x''yyyy_MM_ddHH:mm_ss')
'x'yyyy_MM_ddHH:mm_ss

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카테고리

도움말 센터File Exchange에서 Time Series Objects에 대해 자세히 알아보기

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질문:

2017년 12월 19일

편집:

2017년 12월 19일

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