How to use quadprog for a function with time dependent constant?

조회 수: 3 (최근 30일)
Jan Willem de Lange
Jan Willem de Lange 2017년 12월 17일
댓글: Matt J 2017년 12월 17일
I have an optimization problem where to goal is to minimize the following equation:
f(x) = aβx² - ax + ay + b
where a, b and β are constants and y is a vector of constants. x is the decision variable and is also a vector of the same length as y. To use quadprog to solve this problem, this has to be in the form
f(x) = 1/2 xHx + fx
How do I put my equation in that form when it has the constant in the form of a vector?
Thanks very much!
  댓글 수: 1
Matt J
Matt J 2017년 12월 17일
It is not clear how your f(x) works out to be scalar-valued. If it is not scalar-valued, quadprog is not applicable and, in fact, it is fundamentally unclear what it means to "minimize" it.

댓글을 달려면 로그인하십시오.

답변 (1개)

Matt J
Matt J 2017년 12월 17일
편집: Matt J 2017년 12월 17일
Don't bother. The minimizing x in your case is given trivially by
xmin=1./(2β)
and the minimum value is then f(1./(2β))

카테고리

Help CenterFile Exchange에서 Quadratic Programming and Cone Programming에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by