Why do I get the error "Too many input arguments"
조회 수: 2 (최근 30일)
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my_recorder = audiorecorder;
recordblocking(my_recorder,2)
x= getaudiodata(my_recorder);
LPF0=LPF;
x0=filter(LPF0,Num_LPF,1,x);
Code written above is my matlab code.
But when I activated this, "Too many input arguments" message is shown on the command window.
How can I solve this problem?
function Hd = LPF
% MATLAB Code
% Generated by MATLAB(R) 9.2 and the Signal Processing Toolbox 7.4.
% Generated on: 08-Dec-2017 11:47:53
% Equiripple Lowpass filter designed using the FIRPM function.
% All frequency values are in Hz.
Fs = 48000; % Sampling Frequency
Fpass = 200; % Passband Frequency
Fstop = 300; % Stopband Frequency
Dpass = 0.057501127785; % Passband Ripple
Dstop = 0.0001; % Stopband Attenuation
dens = 20; % Density Factor
% Calculate the order from the parameters using FIRPMORD.
[N, Fo, Ao, W] = firpmord([Fpass, Fstop]/(Fs/2), [1 0], [Dpass, Dstop]);
% Calculate the coefficients using the FIRPM function.
b = firpm(N, Fo, Ao, W, {dens});
Hd = dfilt.dffir(b);
% [EOF]
and this is my LPF.
댓글 수: 2
KSSV
2017년 12월 8일
Which line shows the error? How did you run the code? It doesn't show any error in my pc.
답변 (1개)
Honglei Chen
2017년 12월 8일
It should just be
x0=filter(LPF0,x);
the coefficients is already in LPF0.
HTH
댓글 수: 1
Abhinaba Dey
2018년 3월 11일
Error using filter2 Too many input arguments.
Error in find_sift (line 48) I_X = filter2(G_X, I, 'same'); % vertical edges
I get the same error. How can I solve it??
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