How can I make this plot smooth?

a=5.51*(10^-10);
h=6.62*(10^-34)
E=linspace(100,1.6e-16,200)
m=9.11e-31
h=6.62*(10^-34);
A=sqrt(2*m*E)/h;
f=(16*(sin(A*a)./(A*a)))+cos(A*a);
plot(A,f)

답변 (1개)

Walter Roberson
Walter Roberson 2017년 12월 4일

0 개 추천

You have
E=linspace(100,1.6e-16,200)
which is 200 values linearly decreasing from 100 to 1.6E-16. You calculate A proportional to sqrt(E) so A will be proportional to 10 to about 1.26E-8 in sqrt-linear steps. You then divide by A. But dividing by sqrt-linear does not give linear or sqrt-linear: the distance between adjacent 1/A for small A near 1E-8 is going to be much much greater than the distance between adjacent 1/A for large A near 10.
The only way to make the resulting plot smooth is to use E values such that after transformation are linear. For example,
maxE = 100;
minE = 1E-16;
Ar_maxE = 1 ./ (sqrt(2*m*maxE) ./ h);
Ar_minE = 1 ./ (sqrt(2*m*minE) ./ h);
Ar = linspace(Ar_maxE, Ar_minE, 200);
A = 1 ./ Ar;
f = 16 * sin(A .* a) ./ a .* Ar + cos(A .* a);

댓글 수: 2

Walter Roberson
Walter Roberson 2017년 12월 4일
I did not divide by Ar, I multiplied by Ar, which is constructed to be a linearly smooth version between the extremes of 1/A.
SHEREEN AHMED
SHEREEN AHMED 2017년 12월 5일
편집: SHEREEN AHMED 2017년 12월 5일
So, what's wrong with it? Note: It has to produce like a decaying cosine wave with different range.

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Interpolation에 대해 자세히 알아보기

질문:

2017년 12월 4일

편집:

2017년 12월 5일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by