Why does a'*b yield a (slightly) different result than dot(a,b)?

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EQ
EQ 2017년 11월 28일
답변: Walter Roberson 2017년 11월 28일
I was working an building a matrix entry-wise and checking two different methods against each other and eventually found that dot(a,b) is giving me a different answer than a'*b, where a and b are both real 9948x1 column vectors. I can see that the implementation of dot uses conj(a)*b, but my vectors are real. In one example, dot(a,b) = -1.0351e-11 and a'*b = -8.6402e-12.
I think it's likely a floating point precision issue, but I'm curious about the implementation of the "*" operator and what might be leading to it. Can anyone shed some light on this?
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EQ
EQ 2017년 11월 28일
I'm attaching two vectors a and b that show the issue. I'm using R2015b.
Guillaume
Guillaume 2017년 11월 28일
Indeed with your inputs I get the same discrepancy in R2017b. No idea why.

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Walter Roberson
Walter Roberson 2017년 11월 28일
For sufficiently large arrays, a'*b is going to invoke the high performance libraries, which are going to calculate the multiplications in multiple threads, doing partial summations, before eventually doing a final summation. Because the summations could be done in a different order than sum(conj(a).*b), the round-off can be different.

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