Calculation speed
이전 댓글 표시
I tried making a very simple algorithm for testing the computers speed, like this
tic;
for r = 1:2000;
for c = 1:2000;
A(r,c) = r^2+sqrt(c);
end
end
toc
And it's obviously on purpose that I didn't preallocate A, since I want to stress the processor a bit. Anyway, i ran it on three different computers with follow results:
University desktop, with Ubuntu and Matlab 2010b. Time ~18 sek
Home desktop, with Windows and Matlab 2011 (i think). Time ~7 sek
Home laptop, with Ubuntu and Matlab 2011 or 2012 (dont remember) Time ~4 sek
The thing that confuses me a bit, is that my Laptop is that much faster than my home desktop, since both processor, graphics card and ram should be superior on the home desktop. Can anyone help me solve this mystery?
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추가 답변 (4개)
Daniel Shub
2012년 4월 27일
Why not just use bench?
doc bench
Your lack of preallocation is probably distorting your results for your university desktop since automatic array growth gets a lot faster in R2011a
As for your two home machines, again the version may matter since MATLAB is always improving the JIT.
댓글 수: 1
Jan
2012년 4월 27일
It is a disadvantage, that BENCH changes its problem sizes, such that the results are not comparable. But inspite of this, BENCH is still a more reliable measurement than populating an not-allocated array. +1
Andreas Goser
2012년 4월 27일
1 개 추천
Other contributing factors could be
- 32/64 architecture of machine in combination of 32/64 MATLAB
- BLAS routines, e.g. the MKL library for Intel processors
Jakob Sørensen
2012년 4월 27일
0 개 추천
댓글 수: 2
Daniel Shub
2012년 4월 27일
So you are using a recommendation I gave, but you accepted Jan's answer and didn't even give me an upvote :(
Jakob Sørensen
2012년 4월 27일
Jeremy Irons
2018년 2월 13일
clear all;
theta=0.002;
lambda1=0.0005;
lambda2=0.0008;
lambda3=0.0012;
I0=1;
x=linspace(-0.2,0.2);
I1=I0*(cos((pi./2)+(2.*pi.*x.*tan(theta))/lambda1).^2);
I2=I0*(cos((pi./2)+(2.*pi.*x.*tan(theta))/lambda2).^2);
I3=I0*(cos((pi./2)+(2.*pi.*x.*tan(theta))/lambda3).^2);
plot(x,I1,x,I2,x,I3)
legend('lambda=0.0005','lambda=0.0008','lambda=0.0012');
댓글 수: 3
Jeremy Irons
2018년 2월 13일
%2
clear all;
D=4000;
lambda=0.05;
I0=1;
d=5;
a=4;
tx=-80:1:80;
ty=tx;
[X,Y]=meshgrid(tx,ty);
I1=I0.*((sin((pi.*d.*Y)./(lambda.*D)))./((pi*d*Y)/(lambda.*D))).^2*I0.*((sin((pi.*d.*X)./(lambda.*D)))./((pi*d*X)/(lambda.*D))).^2;
hold on;
subplot(2,1,1)
surf(X,Y,I1)
xlabel('x')
ylabel('y');
subplot(2,1,2)
contour(X,Y,I1,200)
xlabel('x')
ylabel('y');
Jeremy Irons
2018년 2월 13일
%3
clear;
Na = 6.022*10^23;
kB = 1.38*10^-23;
u = 1.66*10^-27;
mH2 = 2*u;
mO2 = 32*u;
mN2 = 28*u;
v = 0:2000;
fvH2 = 4.*pi.*(mH2./(2.*pi.*kB.*300)).^(3./2).*v.^2.*exp(-(mH2.*v.^2)./(2.*kB.*300));
fvO2 = 4.*pi.*(mO2./(2.*pi.*kB.*300)).^(3./2).*v.^2.*exp(-(mO2.*v.^2)./(2.*kB.*300));
fvN2 = 4.*pi.*(mN2./(2.*pi.*kB.*300)).^(3./2).*v.^2.*exp(-(mN2.*v.^2)./(2.*kB.*300));
fvH2_2 = 4.*pi.*(mH2./(2.*pi.*kB.*70)).^(3./2).*v.^2.*exp(-(mH2.*v.^2)./(2.*kB.*70));
fvH2_3 = 4.*pi.*(mH2./(2.*pi.*kB.*500)).^(3./2).*v.^2.*exp(-(mH2.*v.^2)./(2.*kB.*500));
subplot(2,1,1);
hold on;
plot(v,fvH2)
plot(v,fvO2)
plot(v,fvN2)
xlabel('v [m/s]');
ylabel('f(v)');
legend('H2','O2','N2');
subplot(2,1,2);
hold on;
plot(v,fvH2)
plot(v,fvH2_2)
plot(v,fvH2_3)
xlabel('v [m/s]');
ylabel('f(v)');
legend('300K','70K','500K');
Andrew Jordan
2018년 2월 13일
1
clear all;
theta = 0.002;
lambda = [0.0005, 0.0008, 0.0012];
I0 = 1;
x = linspace(-0.2, 0.2);
I1 = I0*(cos((pi./2)+(2.*pi.*x.*tan(theta))/lambda(1)).^2);
I2 = I0*(cos((pi./2)+(2.*pi.*x.*tan(theta))/lambda(2)).^2);
I3 = I0*(cos((pi./2)+(2.*pi.*x.*tan(theta))/lambda(3)).^2);
plot(x, I1, x, I2, x, I3)
xlabel('X');
ylabel('I');
legend('0.0005','0.0008','0.0012');
title('Rozklad natezenia');
for j = length(lambda)
d(j) = lambda(j)/sin(theta);
end
figure
plot(lambda, d)
title('d(lambda)')
xlabel('Dlugosc swiatla lambda')
ylabel('Odleglosc d')
2
clear all;
D = 4000;
lambda = 0.05;
I0 = 1;
d = 5;
a = 4;
tx = -75:1:75;
ty = -75:1:75;
[X,Y] = meshgrid(tx,ty);
I = I0.*((sin((pi.*d.*Y)./(lambda.*D)))./((pi*d*Y)/(lambda.*D))).^2*I0.*((sin((pi.*d.*X)./(lambda.*D)))./((pi*d*X)/(lambda.*D))).^2;
hold on;
subplot(1,2,1)
surf(X,Y,I)
title('Rozklad natezenia')
xlabel('x')
ylabel('y');
zlabel('I')
subplot(1,2,2)
contour(X,Y,I,200)
title('Kontur natezenia')
xlabel('x')
ylabel('y');
zlabel('I')
hold off;
3
clear;
Na = 6.022*10^23;
kB = 1.38*10^-23;
u = 1.66*10^-27;
mH = 2*u;
mO = 32*u;
mN = 28*u;
v = 0:5000;
fH = 4.*pi.*(mH./(2.*pi.*kB.*300)).^(3./2).*v.^2.*exp(-(mH.*v.^2)./(2.*kB.*300));
fO = 4.*pi.*(mO./(2.*pi.*kB.*300)).^(3./2).*v.^2.*exp(-(mO.*v.^2)./(2.*kB.*300));
fN = 4.*pi.*(mN./(2.*pi.*kB.*300)).^(3./2).*v.^2.*exp(-(mN.*v.^2)./(2.*kB.*300));
fK70 = 4.*pi.*(mH./(2.*pi.*kB.*70)).^(3./2).*v.^2.*exp(-(mH.*v.^2)./(2.*kB.*78));
fK500 = 4.*pi.*(mH./(2.*pi.*kB.*500)).^(3./2).*v.^2.*exp(-(mH.*v.^2)./(2.*kB.*500));
subplot(2,1,1);
hold on;
plot(v,fH)
plot(v,fO)
plot(v,fN)
title('Rozklad predkosci czastek gazu Maxwella temperaturze 300K');
xlabel('v [m/s]');
ylabel('f(v)');
legend('H2','O2','N2');
subplot(2,1,2);
hold on;
plot(v,fK70)
plot(v,fH)
plot(v,fK500)
title('Rozklad predkosci czastek gazu Maxwella dla H2');
xlabel('v [m/s]');
ylabel('f(v)');
legend('Temperatura = 78K', 'Temepratura = 300K', 'Temperatura = 500K')
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