Approximation not falls within the expected range

조회 수: 2 (최근 30일)
Zhuoying Lin
Zhuoying Lin 2017년 11월 14일
편집: Walter Roberson 2024년 12월 4일
Here's my script:
n=1;
while abs(pi-sum(4./((2*(1:n)-1).*(-1).^((1:n)+1))))>0.001
n=n+1;
end
fprintf('The approximation using Leibniz''s formula falls within 0,001 of pi when it equals to\n')
fprintf('%.9f with n equls %d\n\n',sum(4./((2*(1:n)-1).*(-1).^((1:n)+1))),n)
end
As shown, I try to make the result falls within 0.001 of pi, however, I get n=1000 an approximation equals 3.140592654.
My friend gets n=2002, so is mine wrong?
Thank you!

답변 (1개)

ag
ag 2024년 12월 4일
Hi Zhuoying,
I kindly suggest you to refer the following MathWorks file exchange page, which demonstrates implementation of the Leibniz formula: Approximation of Pi - https://www.mathworks.com/matlabcentral/fileexchange/102659-approximation-of-pi-leibniz-formula
You can find the code on the "Functions" tab.
Hope this helps!

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by