how can i plot the graph for the following code

nb_user = 5;
sub_used = 3;
nb_sub = sub_used * nb_user;

association = zeros(nb_user,nb_sub);

throughput_thre = 0;
sub_order = [1 1 1 2 2 2 3 3 3 4 4 4 5 5 5];

for s = 1:nb_user
    association(s,((s-1)*sub_used+1):(s*sub_used)) = ones(1, sub_used);
end

for s = 1:nb_user
    for k = 1:nb_sub
       if association (s,k) == 1
           throughput(s,k) = 3*sub_order(k);  
       end
    end
end
 u =0;
for s = 1:nb_user
    for k = 1:nb_sub
           u = u + throughput(s,k);   
    end
end

          association;
          throughput;

Answer 1

[KSSV]

nb_user = 5;
sub_used = 3;
nb_sub = sub_used * nb_user;
association = zeros(nb_user,nb_sub);
throughput= zeros(nb_user,nb_sub);
throughput_thre = 0;
sub_order = [1 1 1 2 2 2 3 3 3 4 4 4 5 5 5];
for s = 1:nb_user
    association(s,((s-1)*sub_used+1):(s*sub_used)) = ones(1, sub_used);
end
for s = 1:nb_user
    for k = 1:nb_sub
        if association (s,k) == 1
            throughput(s,k) = 3*sub_order(k);
        end
    end
end
u =0;
for s = 1:nb_user
    for k = 1:nb_sub
        u = u + throughput(s,k);
    end
end

x = 1:nb_user ;
y = 1:nb_sub ;
[X,Y] = meshgrid(x,y) ;

figure
surf(X,Y,association') ;
figure
surf(X,Y,throughput') ;

[Prabha Kumaresan]

with respect to the code i am getting figure and i have attached it. could you tell me the figure explanation

[KSSV]

@Prabha....it is you who gave the code.....and asked to plot..that's the way to plot.....it is you, who have to explain......:)

[Prabha Kumaresan]

yes,I want to draw the graph in two dimensional.Is it possible for the above code to be drawn in 2D graph.

[KSSV]

That's what it does..it plots a surface....as you have two dependent parameters.

[Prabha Kumaresan]

i am getting the graph in 3 dimensional view but i want to be drawn with respect to x and y axis. how can i able to convert from x,y and z axis to x and y axis.