filtering out two months with a code

조회 수: 2 (최근 30일)
AA
AA 2017년 11월 1일
답변: dpb 2017년 11월 1일
dateless = Dates(nomatch);
datelike = Dates(~nomatch);
dateliketime=datetime(datelike);
liatime=dateliketime.Month == 10;
datelike1= datelike(liatime,1);
Here I select the month November from the group that is available. What if I want to select two months, i.e. November and October? Is there any way to display this?

채택된 답변

dpb
dpb 2017년 11월 1일
Month1 == 10; % make variables instead of hardcoded
Month2 == 11; % "magic" numbers
datelike1= datelike(iswithin(dateliketime.Month,Month1,Month2));
where iswithin is my "syntactic sugar" utility
function flg=iswithin(x,lo,hi)
% returns T for values within range of input
% SYNTAX:
% [log] = iswithin(x,lo,hi)
% returns T for x between lo and hi values, inclusive
flg= (x>=lo) & (x<=hi);
If you convert your dates to datetime class, there is a "veritable plethora" of functions specifically for handling dates, date arithmetic and logic, including isbetween

추가 답변 (1개)

Cam Salzberger
Cam Salzberger 2017년 11월 1일
In this code snippet, liatime will be a logical array, with true anywhere dateliketime.Month is 10, and false anywhere it isn't. So a good place to start looking would probably be under MATLAB's logical operations.
For your specific question, the logical OR operator (non-short-circuit version) should be sufficient:
liatime = dateliketime.Month == 10 | dateliketime.Month == 11;
-Cam

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