- Why do you need that?
- See TUTORIAL: Why Variables Should Not Be Named Dynamically (eval)
How to name every row of 100*2500 matrix?
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currently i am working with a matrix. The dimension of the matrix is 100*2500. I need to assign each row the matrix to a new variable. How i can do this?
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Les Beckham
2017년 11월 1일
But Matlab is designed to allow you to operate on matrices and (more specifically, in this case) subsets of matrices using indexing. That is what per has suggested and, I think, you should try. You don't need to give a separate name like row1 to data(1,:), etc. -- just apply your operation to data(1,:), probably using a loop where the 1 is replaced by the loop index. Then you don't have to code a hundred lines to process row1 through row100.
Please note especially the last bullet in per's last comment.
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per isakson
2017년 11월 1일
편집: per isakson
2017년 11월 1일
"So all I want is as followings" See TUTORIAL: Why Variables Should Not Be Named Dynamically (eval). However, I guess you need to make your own mistakes to understand that it's a really bad idea.
M = ones( 3, 5 );
for rr = 1 : size(M,1)
variable_name = sprintf( 'row%03d', rr );
assign( variable_name, M(rr,:) );
end
where
function assign( varargin )
switch nargin
case { 2 },
if isvarname( varargin{ 1 } )
Name = varargin{ 1 };
else
error( ['poi: First input argument, ', ...
inputname(1), ' must be a legal name'] ),
end,
Value = varargin{ 2 };
otherwise
error( 'poi: Wrong number of input arguments' ),
end
assignin( 'caller', Name, Value );
end
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Muhammad Ammar bin Faizul Azli
2020년 11월 27일
@Stephen Cobeldick
May i know what would your code be if i were to do the same for column?
Steven Lord
2020년 11월 27일
With functionality available now, I'd probably use a table array instead of a numeric array.
cities = ["Albuquerque"; "Boston"; "Chicago"; "Dallas"];
dist = array2table(magic(4), 'VariableNames', cities, 'RowNames', cities)
distBC = dist{'Boston', 'Chicago'}
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