If we list all the natural numbers up to 15 that are multiples of 3 or 5, we get 3, 5, 6, 9, 10, 12 and 15. The sum of these multiples is 60. Write a function called sum3and5muls that returns the sum of all the unique multiples of 3 or 5 up to n where n is a positive integer and the only input argument of the function. (Credit: Project Euler)
My answer is;
function sumof = sum3and5muls(n)
sumof = sum([3:3:n])+sum([5:5:n])-sum([15:15:n]);
Fault; Problem 8 (sum3and5muls): Testing with argument(s) 1 Feedback: Your program made an error for argument(s) 1
Your solution is _not_ correct.
What is wrong in my code?

댓글 수: 4

SULE SAHIN
SULE SAHIN 2017년 10월 30일
Okey . this is acceptable
Birdman
Birdman 2017년 10월 30일
There is nothing wrong with the code, it works well. How do you call the function in command line?
Stephen23
Stephen23 2017년 10월 30일
@SULE SAHIN: you do not need to use square brackets, because you are not concatenating anything. Instead of this sum([3:3:n]) you simply need this sum(3:3:n).
Walter Roberson
Walter Roberson 2018년 4월 27일
Please do not close questions that have an answer.

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답변 (1개)

Jan
Jan 2017년 10월 30일
편집: Jan 2017년 10월 30일

0 개 추천

The error message tells you, that the output for n=1 differs from the expectations. Look what your code does in this case. What is 3:3:n then? What is its sum?
What happens for n=3?
3:3:n
5:5:n
15:15:n
What might be the result of:
3 + [] - []
???
Note: 3:3:n is a vector already. There is no need fro additional square brackets, see http://www.mathworks.com/matlabcentral/answers/35676-why-not-use-square-brackets

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