Any tips for bsxfun and repeated calculation?

조회 수: 1 (최근 30일)
Marie
Marie 2017년 10월 29일
댓글: Cedric 2017년 10월 30일
Hello,
I am currently using bsxfun to subtract the first column from matrix A from matrix A itself, which is straightforward. C=bsxfun(@minus,A,B); Say A= [1 2 3; 3 4 1; 1 5 7] and B = [1 3 1]'
I want to do the same for each column and separately stack up the output vertically one matrix after another. In this example, the resulting matrix would thus be:
D= [0 1 2; 0 1 -2; 0 4 6; -1 0 1; -1 0 -3; -4 0 2; -2 -1 0; 2 3 0; -6 -2 0]
Thanks in advance for any advice.

채택된 답변

Cedric
Cedric 2017년 10월 29일
편집: Cedric 2017년 10월 29일
If you have MATLAB R2016b or above, BSXFUN was replaced by automatic expansion and you can do it as follows:
>> D = repmat( A, 3, 1 ) - A(:)
D =
0 1 2
0 1 -2
0 4 6
-1 0 1
-1 0 -3
-4 0 2
-2 -1 0
2 3 0
-6 -2 0
otherwise, almost the same as your first solution:
>> D = bsxfun( @minus, repmat( A, 3, 1 ), A(:) ) ;
Both are based on the fact that indexing A linearly will read it column first:
>> A(:)
ans =
1
3
1
2
4
5
3
1
7
  댓글 수: 2
Marie
Marie 2017년 10월 30일
Thank you for the clear reply; much appreciated!
Cedric
Cedric 2017년 10월 30일
My pleasure!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by