What does "z" stands for in "solve" function?
이전 댓글 표시
Hi everyone, I've been struggling trying to clear f in the next equation using the "solve" function:
syms f G m Q;
eqn = ((f^2)*(m-1))/(sqrt(((m*(f^2)-1)^2)+((f^2)*(((f^2)-1)^2)*((m-1)^2)*(Q^2))))==G;
x = solve(eqn,f)
The answer I get is the following:
x =
root(2*G^2*Q^2*m*z^3 - G^2*Q^2*m^2*z^3 - G^2*Q^2*z^3 - 4*G^2*Q^2*m*z^2 + 2*G^2*Q^2*m^2*z^2 + 2*G^2*Q^2*z^2 - G^2*m^2*z^2 - 2*m*z^2 + m^2*z^2 + z^2 + 2*G^2*Q^2*m*z - G^2*Q^2*m^2*z + 2*G^2*m*z - G^2*Q^2*z - G^2, z, 1)^(1/2)
root(2*G^2*Q^2*m*z^3 - G^2*Q^2*m^2*z^3 - G^2*Q^2*z^3 - 4*G^2*Q^2*m*z^2 + 2*G^2*Q^2*m^2*z^2 + 2*G^2*Q^2*z^2 - G^2*m^2*z^2 - 2*m*z^2 + m^2*z^2 + z^2 + 2*G^2*Q^2*m*z - G^2*Q^2*m^2*z + 2*G^2*m*z - G^2*Q^2*z - G^2, z, 2)^(1/2)
root(2*G^2*Q^2*m*z^3 - G^2*Q^2*m^2*z^3 - G^2*Q^2*z^3 - 4*G^2*Q^2*m*z^2 + 2*G^2*Q^2*m^2*z^2 + 2*G^2*Q^2*z^2 - G^2*m^2*z^2 - 2*m*z^2 + m^2*z^2 + z^2 + 2*G^2*Q^2*m*z - G^2*Q^2*m^2*z + 2*G^2*m*z - G^2*Q^2*z - G^2, z, 3)^(1/2)
-root(2*G^2*Q^2*m*z^3 - G^2*Q^2*m^2*z^3 - G^2*Q^2*z^3 - 4*G^2*Q^2*m*z^2 + 2*G^2*Q^2*m^2*z^2 + 2*G^2*Q^2*z^2 - G^2*m^2*z^2 - 2*m*z^2 + m^2*z^2 + z^2 + 2*G^2*Q^2*m*z - G^2*Q^2*m^2*z + 2*G^2*m*z - G^2*Q^2*z - G^2, z, 1)^(1/2)
-root(2*G^2*Q^2*m*z^3 - G^2*Q^2*m^2*z^3 - G^2*Q^2*z^3 - 4*G^2*Q^2*m*z^2 + 2*G^2*Q^2*m^2*z^2 + 2*G^2*Q^2*z^2 - G^2*m^2*z^2 - 2*m*z^2 + m^2*z^2 + z^2 + 2*G^2*Q^2*m*z - G^2*Q^2*m^2*z + 2*G^2*m*z - G^2*Q^2*z - G^2, z, 2)^(1/2)
-root(2*G^2*Q^2*m*z^3 - G^2*Q^2*m^2*z^3 - G^2*Q^2*z^3 - 4*G^2*Q^2*m*z^2 + 2*G^2*Q^2*m^2*z^2 + 2*G^2*Q^2*z^2 - G^2*m^2*z^2 - 2*m*z^2 + m^2*z^2 + z^2 + 2*G^2*Q^2*m*z - G^2*Q^2*m^2*z + 2*G^2*m*z - G^2*Q^2*z - G^2, z, 3)^(1/2)
But I just don't understand where does the "z" come from or what does it mean. Can anyone please help me out here? Thanks!
채택된 답변
추가 답변 (0개)
카테고리
도움말 센터 및 File Exchange에서 Numeric Solvers에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!