How can i make comparison faster

조회 수: 3 (최근 30일)
Mats
Mats 2017년 10월 26일
댓글: Andrei Bobrov 2017년 10월 26일
My aim with the loop is to pick out all elements of C that are within range r of rd and range t of td (rd and td are range matrices). Then multiply the elements together and add them to a sum.
This loop is called about a million times and is relatively slow.
Does anyone have an idea of how I can increase the speed of the loop? (I have tried code generation which turned out slower, and parallelism)
for i = 1:indN
D = C(rd(ind(i),:)<r & td(ind(i),:)<t); % Check for <r and <t
if (isempty(D)) D=0; end
gSum = gSum + prod(D);
end
Profiling gives that D=C(.. line takes 84,7% of the entire run time (the other lines in the loop next to nothing)
  댓글 수: 1
Jan
Jan 2017년 10월 26일
Please provide some test data. Optimizing code depends on the inputs also. E.g. it matters, if there are repetitions in ind, or if C is a [1e7 x 1e2] or [1e2 x 1e7] matrix.

댓글을 달려면 로그인하십시오.

채택된 답변

Jan
Jan 2017년 10월 26일
index = (rd(ind, :) >= r | td(ind, :) >= t);
D = C;
D(index) = 1;
gSum = sum(prod(D, 2));
  댓글 수: 1
Andrei Bobrov
Andrei Bobrov 2017년 10월 26일
+1! Nice!
Small fixed:
D = ones(numel(ind),1)*C(:)';

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Andrei Bobrov
Andrei Bobrov 2017년 10월 26일
편집: Andrei Bobrov 2017년 10월 26일
[ii,jj] = find(rd(ind,:) < r & td(ind,:) < t);
gSum = sum(accumarray(ii,C(jj),[],@(x)prod(x)));

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by