find the distance from 1 point to all point

Let's say: I have the data A containing of n points

   A=[ 5  5  1      ----> coordinate (x,y,z) of point 1       
       4  5  2      ----> coordinate (x,y,z) of point 2
       1  1  1      ----> coordinate (x,y,z) of point 3
       2  3  1      ----> coordinate (x,y,z) of point 4 
       6  1  7      ----> coordinate (x,y,z) of point 5
       ................................................

       ....... ]    ----> coordinate (x,y,z) of point n

And, I also have point: B(0 2 1).

How to find the Euclidean distance between point B and all points(1,2,3,4,5,...,n) in A.

Example: 

distance between point B and points 1:

=sqrt{(5-0)^2+ (5-2)^2 + (1-1)^2}= 5.83

Answer 1

[Rik]

The implicit expansion introduced in R2016b can make life easier (here it can make the command a bit shorter), but I'm going to assume you don't have it.

distance=sqrt((A(:,1)-B(1)).^2+(A(:,2)-B(2)).^2+(A(:,3)-B(3)).^2);

[ha ha]

You're correct. May I ask you 1 more question? Example: After I find 1000 distance, How can I choose the 10 shortest distance?

[Jan]

@ha ha: Use sort to sort them and then take the first 10 values. If you need the indices also, get the 2nd output of sort.

With auto-expanding since R2016b:

Dist = sqrt(sum((A - B) .^ 2, 2))

[ha ha]

@ Jan Simon. THANK