Asked by hana razak
on 26 Oct 2017

Hi,

I have an array of 15x10. The first half is pData and the second half is nData. How to set the data in order to get this condition;

1. Each column in 'nData' should have k = '01'

2. Each column in 'pData' should have k = '10'

Here are the data.

26 30 33 36 30 29 28 26 26 27

26 28 30 39 31 28 29 25 29 26

29 32 30 42 32 32 32 26 33 24

30 33 31 43 32 33 33 26 34 24

27 33 37 41 35 31 31 29 30 30

26 35 37 43 33 30 30 29 30 32

23 37 33 40 32 27 32 29 31 34

21 38 32 39 32 27 33 29 32 35

32 28 26 27 26 27 26 27 29 27

36 31 27 29 30 30 30 31 31 30

34 30 28 28 28 30 30 35 30 31

33 29 29 28 27 29 30 36 30 32

30 27 27 26 26 26 25 28 31 27

34 30 30 26 27 30 27 32 34 31

34 27 30 25 28 32 28 36 32 29

This is how I write to divide the array and to treat each column as above condition.

for i = 1:length(data)

for n_data = data(:,6:10,1)

k(i) = 01;

end

for p_data = data(:,1:5,1)

k(i) = 10;

end

end

This code doesn't give the expected results as below,

k

10 10 10 10 10 01 01 01 01 01

Please help me to solve this problem. Thank you

Hana

Answer by Andrei Bobrov
on 26 Oct 2017

Accepted Answer

A = randi([25 50],15,10);

k = {'10','01'};

n = size(A,2);

k = k(ceil(2*(1:n)/n));

Answer by KSSV
on 26 Oct 2017

Let A be your 15x10 matrix.

B = ones(size(A)) ;

B(:,1:5) = 10 ;

hana razak
on 26 Oct 2017

Thanks for your quick reply.

I've checked using your given code.It turns out to be 10(15x5) and 1(15x5).

I don't want to change each element of array A.

I need to appoint for each column from 1 to 5 to have the value of k = '10' and

each column from 6 to 10, to have the value of k = '01'.

In another way, I want it to be like this;

(:,1) -> k = 10

(:,2) -> k = 10

.

.

.

(:,5) -> k = 10

(:,6) -> k = 01

(:,7) -> k = 01

.

.

.

(:,10) -> k = 01

Do you have any idea to do it?

Thank you

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