how to set value for each column?

조회 수: 2 (최근 30일)
hana razak
hana razak 2017년 10월 26일
댓글: hana razak 2017년 10월 26일
Hi,
I have an array of 15x10. The first half is pData and the second half is nData. How to set the data in order to get this condition;
1. Each column in 'nData' should have k = '01'
2. Each column in 'pData' should have k = '10'
Here are the data.
26 30 33 36 30 29 28 26 26 27
26 28 30 39 31 28 29 25 29 26
29 32 30 42 32 32 32 26 33 24
30 33 31 43 32 33 33 26 34 24
27 33 37 41 35 31 31 29 30 30
26 35 37 43 33 30 30 29 30 32
23 37 33 40 32 27 32 29 31 34
21 38 32 39 32 27 33 29 32 35
32 28 26 27 26 27 26 27 29 27
36 31 27 29 30 30 30 31 31 30
34 30 28 28 28 30 30 35 30 31
33 29 29 28 27 29 30 36 30 32
30 27 27 26 26 26 25 28 31 27
34 30 30 26 27 30 27 32 34 31
34 27 30 25 28 32 28 36 32 29
This is how I write to divide the array and to treat each column as above condition.
for i = 1:length(data)
for n_data = data(:,6:10,1)
k(i) = 01;
end
for p_data = data(:,1:5,1)
k(i) = 10;
end
end
This code doesn't give the expected results as below,
k
10 10 10 10 10 01 01 01 01 01
Please help me to solve this problem. Thank you
Hana

채택된 답변

Andrei Bobrov
Andrei Bobrov 2017년 10월 26일
A = randi([25 50],15,10);
k = {'10','01'};
n = size(A,2);
k = k(ceil(2*(1:n)/n));
  댓글 수: 1
hana razak
hana razak 2017년 10월 26일
It works!! Thank you very much

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

KSSV
KSSV 2017년 10월 26일
Let A be your 15x10 matrix.
B = ones(size(A)) ;
B(:,1:5) = 10 ;
  댓글 수: 1
hana razak
hana razak 2017년 10월 26일
Thanks for your quick reply.
I've checked using your given code.It turns out to be 10(15x5) and 1(15x5).
I don't want to change each element of array A.
I need to appoint for each column from 1 to 5 to have the value of k = '10' and
each column from 6 to 10, to have the value of k = '01'.
In another way, I want it to be like this;
(:,1) -> k = 10
(:,2) -> k = 10
.
.
.
(:,5) -> k = 10
(:,6) -> k = 01
(:,7) -> k = 01
.
.
.
(:,10) -> k = 01
Do you have any idea to do it?
Thank you

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Logical에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by