changing minutes after midnight into a datetime array
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Suppose you have the matrix minutesaftermid which contains integers that represent the minutes after midnight, e.g. 1,2,3,4,5,6,7,......
How do I convert this format to a datetime array.
t = datetime(Y,M,D,H,MI,S,MS), but I only needs the MI.
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per isakson
2017년 10월 26일
편집: per isakson
2017년 10월 26일
"but I only need the MI" I don't think you can avoid the date and time.
X = 60*[1,2,3,4,5,6,7];
T = datetime( X, 'ConvertFrom','epochtime', 'Epoch','2000-01-01' )
T =
Columns 1 through 4
2000-01-01 00:01:00 2000-01-01 00:02:00 2000-01-01 00:03:00 2000-01-01 00:04:00
Columns 5 through 7
2000-01-01 00:05:00 2000-01-01 00:06:00 2000-01-01 00:07:00
and
>> T.Minute
ans =
1 2 3 4 5 6 7
Remark: the year 2000 is a leap year.
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추가 답변 (2개)
Walter Roberson
2017년 10월 26일
datetime('today') + minutes(minutesaftermid)
if you wanted it to be relative to today (local time)
If you just need minutes after midnight and not any particular day, you should probably be leaving it as a duration array instead of a datetime array.
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Peter Perkins
2017년 11월 16일
datetimes are dates+times. As Walter says, unless you also have a set of dates, or you want 'today', then you likely want a duration array, and so just call the minutes function to create one.
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Peter Perkins
2017년 11월 20일
Ah, right. So you can either add minutes (as you showed), or if you have the date portion as numeric values, you can use the "roll-over" behavior built into the constructor:
>> datetime(2017,11,1:3,0,[1430 1440 1450],0)
ans =
1×3 datetime array
01-Nov-2017 23:50:00 03-Nov-2017 00:00:00 04-Nov-2017 00:10:00
Walter Roberson
2017년 11월 20일
I might...
T = datetime(2017,11,1:3,0,[1430 1440 1450],0, 'TimeZone', 'local');
[H, M] = hms(T);
mins_since_midnight = H * 60 + M
... though I would want to double-check outputs when there are time zone changes. I have now gotten myself confused about what "minutes since midnight" even means when there are time-zone changes.
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