How to sort a matrix based on one index I have ?

t= [ 4 2
     2 6
     6 9]
c= [ 2
     3
     1]

Now, I want to arrange t according to c index; I need to get t nex sorted based on c :

t= [ 2 6
     4 2
     6 9]

Here is what I tried:

h=cell(1,1);
h{1,1}=t;
h{1,1}(c)

The answer I get is just one column sorted, but not the total matrix t.

Answer 1

[Cedric Wannaz]

I guess/hope that you made a mistake when you built your example of sorted t (that seems to be sorted according to c=[2;1;3]). If so, the solution should be:

 t_sorted = t(c,:) ;

[Alla Abdella]

Thank you! It works!!

[Cedric Wannaz]

My pleasure!

Answer 2

[Image Analyst]

You need to negate c and add 4 if you want the results you gave:

t= [ 4 2
  2 6
  6 9]
c= [ 2
  3
  1]
c2 = -c+4
h = t(c2,:)

You'll see:

h =
     2     6
     4     2
     6     9

exactly as you requested. However, I think you may really want Cedric's solution, despite what you actually asked for.