Attempted to access cols3(6); index out of bounds because numel(cols3)=5

Hello, I get an error when I run my code. This is the part that gives me prob. Actually, the length of cols3 in my data can vary depending on the data set I am using. In this specific example, the real length of cols3 is 5.

for i=1:length(cols3)
 dat{i}=newdata(1:6,cols3(i):cols3(i+1));
end

[KSSV]

What is newdata? Here is the problem.

[Paola]

newdata is a 6XN matrix. The above is not the complete code. Actually the whole code doesn't give me errors. Only when I add this "for" at the end...

Answer 1

[Guillaume]

Well, yes your code is never going to work, you set i to iterate from 1 to the numbers of elements in cols3, yet you access cols3(i+1). When i is equal to the index of the last element then cols3(end+1) is not valid.

One possible way to fix this may be to stop at the end-1:

for i = 1 : numel(cols3)-1   %numel is safer than length

[Paola]

Thanks a lot!