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There is a program I have one part I have to modify, could anyone help with this?
function y = run (lambda, n_mea, n_smpls_per_mea)
global xacc hist bin_range bin_size n_bins bin_size_inv midpt bin
% define parameters and procedures for histogram:
bin_range = 6.0 * lambda %NOTE: prefactor can be changed
bin_size = 0.1 * lambda %NOTE: prefactor can be changed
n_bins = floor(bin_range/bin_size)+1
bin_size_inv = 1.0/bin_size
% bin is a function: bin(x) provides the bin number for x:
bin =@(x)(min(floor(x*bin_size_inv)+1,n_bins))
% hist accumulates the number of entries in each bin:
hist = zeros(1,n_bins)
xacc = [n_mea]
for m=1:n_mea
xacc(m)=0
for n=1:n_smpls_per_mea
% unifrnd(0,1) gives a random uniform on (0,1)
ranxi = unifrnd(0,1)
% ranexp gives exponential distribution
ranexp = ranxi
% *^^^^^^^^^ <-- MODIFY -- fill in correct form**
xacc(m) = xacc(m) + ranexp
bi = bin(ranexp)
hist(bi) = hist(bi) +1
end
xacc(m) = xacc(m)/n_smpls_per_mea
end
midpt = 0.5*bin_size:bin_size:(n_bins-0.5)*bin_size
end
댓글 수: 8
Before we can attempt to help:
What do you need to modify?
What is the correct form?
" *% *^^^^^^^^^ <-- MODIFY -- fill in correct form**
What is the error message, if any?
Have you heard of camelcase notation of variables? It'll make codes easier to read because tracking underscores in variable names is just confusing. Read this https://en.wikiversity.org/wiki/CamelCase.
midpt = 0.5*bin_size:bin_size:(n_bins-0.5)*bin_size
midpt = 0.5*binSize:binSize:(nBins-0.5)*binSize
Also:
- do not use hist as a variable name because hist is a matlab function.
- instead of unifrnd(0, 1), you could use rand() for a uniform number between 0 to 1.
Gaëtan Poirier
2017년 10월 2일
OCDER
2017년 10월 2일
Have you looked up this on the google search?
"matlab exponential distributed random number"
Gaëtan Poirier
2017년 10월 2일
Jan
2017년 10월 2일
Whenever you mention an error in the forum, post a complete copy of the message, not just a part of it.
Gaëtan Poirier
2017년 10월 2일
Walter Roberson
2017년 10월 2일
mkhist is not called from the code that you posted.
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