May you help me please to continue my syytem seconder order DE function?
조회 수: 1 (최근 30일)
이전 댓글 표시
function [dF1dx,dF2dx]=funode1(x,F)
dF1dx=[F1(2);(Q/K1)*F1(1)-P/K1];
dF2dx=[F2(2);(Q/K2)*F2(1)-P/K2];
function res12=myfunbc12(F1a,F1b,F2a,F2b)
res=[F1a(1);F1b(1)-F2b(1);F2a(1);F1a(2)-F2b(2)];
The boundary conditions are as follows
F1(0)=0;
F2(l)=0;
F1(l-u)=F2(l-u);
dF1/dx(l-u)=dF2/dx(l-u))
If this is true how to continue?
댓글 수: 2
John D'Errico
2017년 9월 30일
How to continue with what? You have code. Does it do what you need? If not, then what does it lack? How can we read your mind?
답변 (1개)
Josh Meyer
2017년 10월 2일
Since you have boundary conditions you'll want to use bvp4c or bvp5c. See Boundary Value Problems in the doc for more info.
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Boundary Value Problems에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!