How to write a code for varying step size ?
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Hi! I'm working on boundary layer theory.I've written a code for solving block tri-diagonal matrix.One of the variable i've taken with variable step size to get a good accuracy.Have used if loop .While executing it takes the first if condition and executes for the whole interval as my initialization is 0.As my incremental value is the varying parameter how to bring it?
x_bar=0;
if x_bar<=0.5
delx_bar=0.01;
elseif x_bar >=0.5 && x_bar <=1.25
delx_bar=0.005;
else
delx_bar=0.0001;
end
%%Intial profiles start
x_bar=0:delx_bar:1.25;
n_xbar=length(x_bar);
As I've used x_bar and length of x_bar in the code for calculation of values i need to define it. What changes do I have to make so that my x_bar values are generated first and then the successive delx_bar are taken for calculation of values.
댓글 수: 1
James Tursa
2017년 9월 26일
What do you want for a result? A vector x_bar that starts at 0, then grows by 0.01 until it reaches the value 0.5, then grows by the value 0.005 until it reaches the value 1.25, then grows by 0.0001 until it reaches some final value?
채택된 답변
Andrei Bobrov
2017년 9월 27일
편집: Andrei Bobrov
2017년 9월 27일
Xb = [0, .5, 1.25, 2];
dx = [.01, .005, .0001];
x_bar = cumsum([Xb(1), repelem(dx,diff(Xb)./dx)]);
>> x_bar_j = 1.589
delx_bar_j = dx(discretize(x_bar_j,Xb))
x_bar_j =
1.589
delx_bar_j =
0.0001
>>
댓글 수: 2
Andrei Bobrov
2017년 9월 29일
Hi Revathy!
If this answer solve problem from your question, please, "accept" him.
추가 답변 (3개)
James Tursa
2017년 9월 26일
편집: James Tursa
2017년 9월 26일
Does this do what you want? (Using arbitrary final value of 2.000 for example)
xstart = 0.000; xend = 0.500; dx = 0.01;
part1 = linspace(xstart ,xend,round((xend-xstart)/dx)+1);
xstart = 0.500; xend = 1.250; dx = 0.005;
part2 = linspace(xstart+dx,xend,round((xend-xstart)/dx) );
xstart = 1.250; xend = 2.000; dx = 0.0001;
part3 = linspace(xstart+dx,xend,round((xend-xstart)/dx) );
x_bar = [part1,part2,part3];
Suganthi D
2021년 10월 7일
Hi professor , a very happy morning. I have written a code for step input variation for 10 houses ..Time for 24 hours. But i do not is this correct or not.. I need your help .. Here I have attached the code .. I want the graph for 10 houses step variation at 24 hours.. how to write the code for tis one..
T=1:1:24; %hours
input = createStep('StepTime',5,'StepSize',5,'FinalTime',25)
plot(input);
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AKASH KUMAR
2022년 3월 1일
clc
clear
close all
%% Variable step size
Step_0=2;
Step=Step_0;
ii=1;theta=0;
while true
theta= theta+Step;
th(ii)=(theta);
Y(ii)=sind(th(ii));
if Y(ii)>0.7 || Y(ii) <-0.7
Step=1/10*Step_0;
else
Step=Step_0;
end
ii=ii+1;
if theta>180*2
break
end
end
plot(th,Y,'.')
grid on;
xlabel('theta(deg)');
댓글 수: 1
Janet onoja
2023년 4월 4일
I having been trying to get code on variable step size using adams method but I can't. Any help please.
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