Matlab code to find optimal solution for A and B

조회 수: 3 (최근 30일)
Ellaf h.s
Ellaf h.s 2017년 9월 17일
편집: Walter Roberson 2017년 9월 18일
Hi i want to find the optimal solution for A and B ?
function[V,A-opt,B-opt]=test(M)
A1=max(M(:,1));
A2=max(M(:,2));
B1=min(M(1,:));
B2=min(M(2,:));
[C,row]= min(max(A1,A2));
[C,col]=max(min(B1,B2));
if min(A1,A2)==max(B1,B2)
fprintf('There is a saddle point')
V=max(B1,B2);
else fprintf('There is no saddle point')
x1=abs(M(1,1)-M(1,2));
y1=abs(M(2,1)-M(2,2));
x2=abs(M(1,1)-M(2,1));
y2=abs(M(1,2)-M(2,2));
fprintf('the game value')
V=(M(1,1)*y1/(x1+y1))+(M(2,1)*x1/(x1+y1))
end
end
  댓글 수: 1
John D'Errico
John D'Errico 2017년 9월 17일
편집: John D'Errico 2017년 9월 17일
Note that A-opt (as well as B-opt) are NOT valid variable names in MATLAB.
You can use an underscore in a name, thus A_opt is valid, if you insist on that name form. But the - symbol is not valid anywhere in a name.
As far as solving the question at hand, it is not obvious what you mean by optimal. Optimality requires that you postulate some well posed metric to determine what is good versus bad. So without knowing what you intend by the word optimal, it is impossible to answer your question. We are not even told what the code you show is intended to do.

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

Help CenterFile Exchange에서 Particle Swarm에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by