Print numbers on an array that have a unique row and column

The code I wrote can print 1's on a unique column but can be on the same row. How could I get it to have a unique row?

 for k=1:N             % Loops N times 
random = randi([1,N]); % Chooses a random number between 1 and board size
X(k,random) = 1;       % Places a 'queen' on a random column 
end

Answer 1

[Jan]

Perhaps you want:

index = randperm(8, 8);
X     = zeros(8, 8);
for k = 1:8
  X(k, index(k)) = 1;
end

0  0  0  0  0  0  1  0  
0  1  0  0  0  0  0  0  
0  0  0  0  0  0  0  1  
0  0  0  0  0  1  0  0  
0  0  0  0  1  0  0  0  
1  0  0  0  0  0  0  0  
0  0  0  1  0  0  0  0  
0  0  1  0  0  0  0  0

Alternatively without a loop:

X = zeros(8, 8);
X(sub2ind([8,8], 1:8, randperm(8, 8))) = 1

Answer 2

[Image Analyst]

Try this:

X = zeros(8, 8); % Initialize
rc = randi([1,8], 1, 2) % One location on the board.
X(rc(1), rc(2)) = 1  % Assign a queen to that square

[Shawn Blancett]

X =

     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0
     0     0     0     0     0     1     0     0

[Shawn Blancett]

typically getting this output with the 1 in a random spot on the bottom row

[Image Analyst]

It won't always be on the bottom row, but it will be on a unique, random row as requested. And in a single, unique random columns also. Is that not what you want? If not, what do you want?

[Shawn Blancett]

Im trying to get a 1 on each row with a unique column. Sorry I didnt clarify.

[Shawn Blancett]

For however big the board size is , that many 1's

[Jan]

I still don't get it: Do you mean a single 1 in each row and in each column?

[Shawn Blancett]

If the board was NxN I want N amount of 1's the board, that have a unique row and column , so no 1 shares a column or row with another 1

Answer 3

[Walter Roberson]

X = zeros(N, N);
available = 1 : N;
for k=1:N             % Loops N times 
   ridx = randi(length(available));
   random = available(ridx);
   available(ridx) = [];
   X(k,random) = 1;       % Places a 'queen' on a random column 
end