Find the indexes of all the zeros or nonzeros in a cell array that contains empty cells

Is there a way to find the indexes of all nonzero elements in a cell that contains empty cells too? I know of the way to first replace all of empty cells with 0 and they use the find and cellfun function. But is there a simpler way? Lets say A={2 5 0 10 0 [] 22 0 13} index=find(~cellfun(@isempty,A)) % index for non-empty cells Is there a way to find indexes for those who contain positive numbers only? Thanks btw using MatLab 2015a

[Stephen23]

Why are you storing numeric data in a cell array? Numeric arrays are the best kind of array for storing numeric data. Note that find is not required if you just want to replace empty arrays with zero:

A(cellfun('isempty',A)) = {0}

Answer 1

[Stephen23]

>> A = {2,5,0,10,0,[],22,0,13};
>> cellfun(@(a)~isempty(a)&&a>0,A)
ans =
  1  1  0  1  0  0  1  0  1

But note that doing numeric operations on the contents of a cell array is quite inefficient. You could be much better off putting numeric data into a numeric array, and then all numeric operations will be much simpler and much more efficient:

>> A = {2,5,0,10,0,[],22,0,13};
>> A(cellfun('isempty',A)) = {NaN};
>> V = [A{:}]
V =
     2     5     0    10     0   NaN    22     0    13
>> V>0
ans =
  1  1  0  1  0  0  1  0  1

[Dennis Huver]

it's working! thanks a ton!!