problem with a matlab code for discrete-time convolution

조회 수: 9 (최근 30일)
Benjamin
Benjamin 2012년 4월 16일
답변: Gui Chen 2021년 1월 21일
Here is my code.
n= -25:25
x= cos(2*pi*n/.3).*(n>=0)
h= (cos(pi*n/.3)+(sin(pi*n/3)/sqrt(3))).*(n>=0)
y= conv(h,x)
plot(n,x)
hold on
plot(n,h)
hold on
plot(n,y)
title ('Plot of input X[n], impulse response h[n] and the convolution of the two Y[n]')
xlabel ('Variable n')
ylabel ('amplitude of signal')
hold on
I have got to plot the input x, impulse response h and the convolution of the two using the conv command but i am getting the error
"??? Error using ==> plot
Vectors must be the same lengths.
Error in ==> lab6p3 at 9
plot(n,y)"
I am using the R2011a student version of matlab
thank you in advance

답변 (3개)

Wayne King
Wayne King 2012년 4월 16일
n= -25:25;
x= cos(2*pi*n/.3).*(n>=0);
h= (cos(pi*n/.3)+(sin(pi*n/3)/sqrt(3))).*(n>=0);
y= conv(h,x);
n1 = -25:length(y)-1-25;
stem(n1,y,'markerfacecolor',[0 0 1]);

Wayne King
Wayne King 2012년 4월 16일
You have to realize the result of linearly convolving two input signals, h and x, is length(h)+length(x)-1
so you need a new n vector that matches your output y in length.
Your y vector has the expected length of length(h)+length(x)-1 = 101
  댓글 수: 1
Benjamin
Benjamin 2012년 4월 16일
How would I do that?
sorry still getting used to matlab

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Gui Chen
Gui Chen 2021년 1월 21일
You should take care of the length after the convolution. You could take a look at this video. https://youtu.be/JlUM0XHTSSQ

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