I have different answer using 'norm'. Do I miss something?

A = [1 2; 3 4];

norm(A) >> 5.4650

But equivalently,

sqrt(1^2 + 2^2 + 3^2 + 4^2) >> 5.4772

the answer is different

Do I miss something? thx!

Answer 1

[Torsten]

norm(A) and norm(A,'fro') are different things.

Best wishes

Torsten.

[penyao lu]

I got it!thanks, Torsten!!

[Stephen23]

@penyao lu: the best way for you to say "thank you" is to accept Torsten's answer.

[penyao lu]

thx for your remind! Stephen.