I have an array of data [ 1.1 0.5 1.8 2.5 0.6 2.0 2.1 4.0 1.3 1.4 5.0 4.2 2.2 3.2 3.4 3.5 3.3 4.8 1.11 2.0 2.5] I need a code pick data points incrementally from 1.1 until it get to the peak then start selecting after the peak in deceasing order.
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I have an array of data [ 1.1 0.5 1.8 2.5 0.6 2.0 2.1 4.0 1.3 1.4 5.0 4.2 2.2 3.2 3.4 3.5 3.3 4.8 1.11 2.0 2.5] I need a code pick data points incrementally from 1.1 until it gets to the peak then start selecting after the peak in decreasing order. The expected outcome is [ 1.1 1.8 2.5 4.0 5.0 4.2 2.2 1.11] starting from the first element (1.1) the next element is 1.8 dropping 0.5 until getting to the peak (5.0) and then start decreasing from 5.0 to 1.11. the number of elements in the final output will reduce.
채택된 답변
Stephen23
2017년 8월 9일
V = [1.1 0.5,1.8,2.5,0.6,2.0,2.1,4.0,1.3,1.4,5.0,4.2,2.2,3.2,3.4,3.5,3.3,4.8,1.11,2.0,2.5];
[~,idx] = max(V);
N = V(1);
X = false(size(V));
for k = 1:idx
X(k) = V(k)>=N;
N = max(V(k),N);
end
for k = idx:numel(V)
X(k) = V(k)<=N;
N = min(V(k),N);
end
Z = V(X);
Generates this output vector:
>> Z
ans =
1.1000 1.8000 2.5000 4.0000 5.0000 4.2000 2.2000 1.1100
Compared to the requested output:
>> [ 1.1 1.8 2.5 4.0 5.0 4.2 2.2 1.11]
ans =
1.1000 1.8000 2.5000 4.0000 5.0000 4.2000 2.2000 1.1100
추가 답변 (1개)
Image Analyst
2017년 8월 9일
1.8 is not an increment of 1.1 above 1.1, and 2.5 is not 1.1 above 1.8. And you can't add any number of 1.1's to 1.1 to get exactly 5. So I'm not sure what rule you're using but it's not [1.1, 2.2, 3.3, 4.4, 5.5, ...] etc.
Anyway, find the max, then use the colon operator:
m = [ 1.1 0.5 1.8 2.5 0.6 2.0 2.1 4.0 1.3 1.4 5.0 4.2 2.2 3.2 3.4 3.5 3.3 4.8 1.11 2.0 2.5]
maxValue = max(m)
% Create vector increasing from 1.1 to the max in steps of 1.1,
% then going down from the max to 1.11 in steps of -0.5:
m2 = [1.1 : 1.1 : maxValue, (maxValue - 0.5) : -0.5 : 1.11]
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