필터 지우기
필터 지우기

Where is the issue in my "while" statement?

조회 수: 1 (최근 30일)
Geo
Geo 2017년 7월 29일
답변: Teja Muppirala 2017년 7월 30일
I want to evaluate the first integer evenly divisible by 3 and 5 using a Matlab code. My attempt is the following:
n=1;
while mod(n,5)~=0 && mod(n,3)~=0
n=n+1;
end
n
I'm new to Matlab and wondering where the issue here is. The code returns n=3 for some reason. I also want to extend this to find the first number evenly divisible by 1-10, for which I wrote the following while loop which also did not return the expected value. Where is my error?
n=1;
while mod(n,1:10)~=0
n=n+1;
end
n
Thank you.
  댓글 수: 3
Geo
Geo 2017년 7월 29일
편집: Geo 2017년 7월 29일
Revision also not working as expected:
n=1;
for k=1:10
while mod(n,k)~=0
n=n+1;
end
end
n
Walter Roberson
Walter Roberson 2017년 7월 29일
found_solution = false;
n = 0;
while ~found_solution
n = n + 1;
found_solution = true;
for k = 1 : 10
if mod(n,k) ~= 0
found_solution = false;
break;
end
end
end
n

댓글을 달려면 로그인하십시오.

답변 (2개)

the cyclist
the cyclist 2017년 7월 29일
편집: the cyclist 2017년 7월 29일
In your second case, you are doing
mod(1,1)
then
mod(2,2)
then
mod(3,3)
and so on, because you are always incrementing n right along with k. Those mod functions are always equal to zero, so they always satisfy the while condition, so you get to n = 10.

Teja Muppirala
Teja Muppirala 2017년 7월 30일
You were on the right track. This gives 2520:
n=1;
while any( mod(n,1:10)~=0 )
n=n+1;
end
n
When your conditional has more than one element, all of them must be true for it to evaluate as true. This will return 'B' and 'C'.
if [1 1 1 0]
disp('A')
else
disp('B')
end
if [1 1 1 1]
disp('C')
else
disp('D')
end

카테고리

Help CenterFile Exchange에서 Graphics Object Programming에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by