Image Processing; converting images

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Damian Wierzbicki
Damian Wierzbicki 2017년 7월 6일
댓글: Damian Wierzbicki 2017년 7월 6일
Hi guys. I have images in .im7 format. I've loaded them into Matlab using PivMat and ReadIMX, then formatted them into .mat files ( images ? ). Now, I'm trying to covert them to either .jpg , .tif , .png , .bmp using imwrite but I cannot do so because 'type was struct'. Can I efficiently go from 'structure' format to any of the formats that imwrite recognizes ?
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KSSV
KSSV 2017년 7월 6일
You have to extract the required pixel information from the structure and use imwrite.
Damian Wierzbicki
Damian Wierzbicki 2017년 7월 6일
Thank you. If you don't mind me asking: what information would that be ? x ( 1x2048 double ) and y ( 1x2048 double ) and also w ( 2048x2048 double) also the unitx and unity are 'mm' - how'd I deal with that ? These are probably really stupid question, but I just want to make sure if I'm doing it wright.

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답변 (2개)

KSSV
KSSV 2017년 7월 6일
You need to pick the matrix 2048*2048 and use imwrite
  댓글 수: 8
Thorsten
Thorsten 2017년 7월 6일
편집: Thorsten 2017년 7월 6일
Imwrite assumes double input data to be in the range [0, 1]. Everything above 1 will be mapped to 1, resulting in an all-white image. So you have to map your data to the range [0, 1].
Damian Wierzbicki
Damian Wierzbicki 2017년 7월 6일
Thank you Thorsten, used mapminmax to map my data to desired range, not sure if that's what you meant ? It now displays the image ok, but with horizontal black thin lines ? There are also, hardly visible, white thin vertical lines along the image ? Any idea what might be causing it ?

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Image Analyst
Image Analyst 2017년 7월 6일
Try this:
storedStructure = load(filename) % Don't use semicolon
% Now extract the image field into its own variable.
rgbImage = storedStructure.myImage; % Or whatever the field for the image is called.
imwrite(rgbImage, 'my RGB image.PNG');
  댓글 수: 1
Damian Wierzbicki
Damian Wierzbicki 2017년 7월 6일
Thank you. I get the same using this method, a white rectangle.

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